Mean median mode 20, 22, 23, 25, 26, 26, 32

Mathematics

1 answer:

elixir [45]3 years ago

6 0

Answer:

mode: 26 median: 25

Step-by-step explanation:

mode: because mode is what appears most, and thats 25

median: is what is in the middle so we cross some numbers off and we get 25

please mark brainliest

You might be interested in

There are four cups of cocoa three friends share them evenly how much does each friend get

Reika [66]

Answer:

1.33

Step-by-step explanation:

4/3

7 0

3 years ago

Read 2 more answers

Example 3 find the local maximum and minimum values and saddle points of f(x, y) = x4 + y4 − 4xy + 1. solution we first locate t

allsm [11]

$f(x,y)=x^4+y^4-4xy+1$

$\begin{cases}f_x=4x^3-4y\\f_y=4y^3-4x\end{cases}$

We have critical points whenever both partial derivatives vanish:

$4x^3-4y=0\implies x^3=y\implies x=y^{1/3}$
$4y^3-4x=0\implies y^3=x=y^{1/3}\implies y^6=y\implies y=0,y=-1,y=1$
$\begin{cases}y=0\implies x=0\\y=-1\implies x=-1\\y=1\implies x=1\end{cases}$

The Hessian is

$\mathbf H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}12x^2&-4\\-4&12y^2\end{bmatrix}$
$\det\mathbf H(x,y)=(12xy)^2-16$

At (0,0), we have $\det\mathbf H(0,0)=-16$ , so (0,0) is a saddle point.

At (-1, -1), we have $\det\mathbf H(-1,-1)=128>0$ and $f_{xx}(-1,-1)=12>0$ , so (-1, -1) is a local minimum.

At (1, 1), we have $\det\mathbf H(1,1)=128>0$ and $f_{xx}(1,1)=12>0$ , so (1, 1) is also a local minimum.

3 0

3 years ago

The height of a cone shaped statue is 9 feet and the diameter is 12 feet .what is the approximate volume of the statue?

dalvyx [7]

Answer:

113.04

Step-by-step explanation:

6*6=36

36*3.14=113.04

4 0

3 years ago

Read 2 more answers