Answer: The required width of the park is 3 miles.
Step-by-step explanation: Given that a 5 mile jogging path diagonal divides a rectangular park in half and the park is 4 miles long.
We are to find the width of the park.
As shown in the attached figure below, the diagonal BD divides the rectangle ABCD into two equal parts,
where length DA = 5 miles, BD = 4 miles and AB = width = ?
Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.
Using Pythagoras theorem in triangle ABD, we have
Thus, the required width of the park is 3 miles.
Answer:
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
Step-by-step explanation:
6x^10 − 96x^2
Factor out 6x^2
6x^2 ( x^8 - 16)
Notice that inside the parentheses we have the difference of squares
6x^2 ( x^4 ^2 - 4^2) a^2 - b^2 = (a-b) (a+b)
6x^2 ( x^4 -4) (x^4 +4)
Notice that x^4-4 is also the difference of squares
6x^2 ( x^2^2 -2^2) (x^4 +4)
6x^2 ( x^2 -2) ( x^2 +2) (x^4 +4)
Note also that x^4 + 4 can be factored into (x^2+2x+2)(x^2-2x+2)
6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)
Answer:
D = 59t
P = 42t
5 hours after noon, darmian is 17 miles closer to the stadium than paisley
Step-by-step explanation:
At noon, Damian is 383 miles away from the stadium and paisley is 315 miles away from the stadium.
Now, we are told that damians speed is 59 mph while paisley's speed is 42 mph.
At t hours after noon, their distance covered will be;
Damian; D = 59t
Paisley; P = 42t
This is because distance = speed × time
Now, 5 hours after noon, their respective distance covered will be;
D(5) = 59 × 5 = 295 miles
P(5) = 42 × 5 = 210 miles
This means that;
distance of Damian from the stadium is; 383 - 295 = 88 miles
Distance of paisley from the stadium is;
315 - 210 = 105 miles
Difference in their distances to the stadium = 105 - 88 = 17 miles
Thus, 5 hours after noon, darmian is 17 miles closer to the stadium than paisley
F+G:
Then, add the elements that occupy the same position:
Solve
So, we find the element at address h31:
In this case, position h31 is - 8.0
