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2 years ago

9

- 3x = 18 answer = m = - 6 answer = 3 4 + y = 0 answer = 2x = - 6 answer = h=2 answer = 5 d = 1 answer = - 8 6 + x = 2 answer =

- 7y = 21 answer = - 9w = 0 answer =

1 answer:

vlada-n [284]2 years ago

4 0

Answer:

this doesnt make sense sorry

Step-by-step explanation:

im trying to help

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The following table shows the number of hours some students in two universities spend reading each week: School A 7 2 3 10 17 14

pychu [463]

The value of $Q_{1}$ , $Q_{2}$ , and $Q_{3}$ for each schools is given in the first picture below.

$Q_{1}$ is the lower quartile
$Q_{2}$ is the median
$Q_{3}$ is the upper quartile

School A:
Minimum value is 2
Maximum value is 22
The lower quartile is 2.5
The median is 10
The upper quartile is 15.5

School B:
Minimum value is 9
Maximum value is 20
The lower quartile is 12
The median is 16
The upper quartile is 18

The box plot for each school is shown in the second picture

Box plot for school A isn't symmetrical. The data tails on the right
Box plot for school B isn't symmetrical. The data tails on the left

8 0

3 years ago

Tickets for an American Baseball League game for 3 adults and 3 children cost less than $75, while tickets for 2 adults and 4 ch

nikitadnepr [17]

<h3>No, the cost of 1 adult ticket cannot be $ 20 and the cost of 1 children ticket is not $ 8.</h3>

Step-by-step explanation:

Let us assume the cots of ticket for 1 adult = $ x

Let us assume the cots of ticket for 1 children = $ y

So, the cost of ticket for 3 adults = 3 x ( Cost of 1 adult ticket) = 3 x

The cost of ticket for 3 children = 3 x ( Cost of 1 children ticket) = 3 y

Also, given the combined cost of 3 adult and children ticket is less than $75.

⇒ 3 x + 3 y < 75 ... (1)

Similarly, the cost of ticket for 2 adults = 2 x

The cost of ticket for 4 children = 4 y

⇒ 2 x + 4 y < 62 ... (2)

Now, solving for the values of x and y, we get:

3 x + 3 y < 75 or, x + y < 25 ⇒ x = 25 - y ( substitute in 2)

2 x + 4 y < 62 or, x + 2 y < 31

⇒ 25 - y + 2 y < 31

or, y + 25 < 31

or, y < 6

⇒ x = 25 - 6 = 19

or, x < 19

So, the cost of 1 adult ticket is x and is less than $19.

The cost of 1 child ticket is y and is less than $6.

Hence, by above statement, NO the cost of 1 adult ticket can not be $ 20 and the cost of 1 children ticket is not $ 8.

4 0

3 years ago

Let f(x) = 1/x . Find the number b such that the average rate of change of f on the interval [2, b] is − 1/8

vekshin1

Answer:

b=4

Step-by-step explanation:

So, we have the function $f(x)=1/x$ . We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

f(2) = 1/(2) = 1/2

So, we have the point (2, 1/2)

At point b, f(b) = 1/b.

Let's plug this into the slope formula:

$\frac{y_2-y_1}{x_2-x_1}=\frac{.5-\frac{1}{b} }{2-b} =-1/8$

Now, we just need to solve for b. First, let's multiply both the numerator and denominator by b (to get rid of the annoying fraction in the numerator).

$\frac{.5b-1}{2b-b^2} =\frac{-1}{8}$

Now, cross multiply.

$4b-8=b^2-2b$

$b^2-6b+8=0$

Solve for b. Factor using the numbers -4 and -2.

$=(b-4)(b-2)=0$

Thus, b=4 or b=2.

However, b=2 is not a possible solution since the interval [2,2] means nothing. Thus, b=4.

4 0

2 years ago

Solve 3x + 2 = 15 for x using the change of base formula log base b of y equals log y over log b. −1.594 0.465 2.406 4.465

disa [49]

<u>Answer:</u>

The value in 3x + 2 = 15 for x using the change of base formula is 0.465 approximately and second option is correct one.

<u>Solution:</u>

Given, expression is $3^{(x+2)}=15$

We have to solve the above expression using change of base formula which is given as

$\log _{b} a=\frac{\log a}{\log b}$

Now, let us first apply logarithm for the given expression.

Then given expression turns into as, $x+2=\log _{3} 15$

By using change of base formula,

$x+2=\frac{\log _{10} 15}{\log _{10} 3}$

x + 2 = 2.4649

x = 2.4649 – 2 = 0.4649

Hence, the value of x is 0.465 approximately and second option is correct one.

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!!

Katena32 [7]

Answer:6018

Step-by-step explanation:

Given Sequence

$-282-266-250-234.....$

It represent an A.P. with

first term $a=-282$

common difference $d=16$

So sum of 51 term

$S_n=\frac{n}{2}[2a+(n-1)d]$

$S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]$

$S_{51}=\frac{51}{2}\times [-564+800]$

$S_{51}=\frac{51}{2}\times [236]$

$S_{51}=51\times 118$

$S_{51}=6018$

7 0

2 years ago