Answer:
The probability is 0.081
Step-by-step explanation:
Here, we want to calculate the probability that the 3rd inspection will be defective.
What this means is that the first two would
not be defective.
Probability of having a defective DVD = 10% = 10/100 = 0.1
Probability of not having a defective DVD = 1 -0.1 = 0.9
So the probability of third being defective = Probability of first not defective * Probability of second not defective * Probability of third defective
= 0.9 * 0.9 * 0.1 = 0.081
Answer:
<em>See the Venn diagram attached</em>
<u>Numbers given:</u>
- <em>Total</em>: 100
- Either a cat of a fish: 70
- Cat: 46
- Cat and fish: 16
<u>Neither a cat or a fish:</u> 100 - 70 = 30
<u>Fish:</u> 70 - (46 + 16) = 70 - 62 = 8
<u>Required probabilities are:</u>
- a) P(neither) = 30/100 = 0.3
- b) P(f) = (16 + 8)/100 = 0.24
- c) P(f not c) = 8/100 = 0.08
The mean is the average.
Add all the number of pets and divide by how many people there were.
3+5+2+4+1
15/number of people
15/5
=3
Hope this helps :)
J
I am 90% sure, if this is edge then this helps me to, I’m really just filling in the character requirement but it’s j, I think
You're very close. However, the less steep line should go through (4,7) and not some point slightly above that location. Also, the shaded region should be above both dashed lines at the same time. So you won't include the portion that I've marked in blue (see attached). Other than that, it looks great.