Parametrically for real t the line is



That's three equations; we substitute into





The intersection is a single point (7,-6,5).
Angle Z is congruent to angle C, so angle C measures 4x+8
the sum of the three angles of a triangle is 180, so
50+2x+40+4x+8=180
6x++98=180
6x=82
x≈13.67
Answer:
There ya go
Step-by-step explanation:
Answer:
i just stole your points thank you
Answer: 8 sq units
Step-by-step explanation:
4 sq units in middle, two triangles on sides are half of four, add two triangles to make whole 4