Question

Axis of symmetry for f(x) = -2x2 + 20x -42

Answer 1

For the function $f(x)=2x^2 +20x-42$

We can use the formula for the axis of symetry, which is $x= \frac{-b}{2a}$

With the values substituted, we get...

$\frac{-20}{2(-2)} =5$

Therefore the axis of symmetry is $x=5$ 

Answer 2

Answer: X=5

Step-by-step explanation:

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