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MrMuchimi
4 years ago
15

Axis of symmetry for f(x) = -2x2 + 20x -42

Mathematics
2 answers:
Ksenya-84 [330]4 years ago
8 0
For the function f(x)=2x^2 +20x-42

We can use the formula for the axis of symetry, which is x= \frac{-b}{2a}

With the values substituted, we get...

\frac{-20}{2(-2)} =5

Therefore the axis of symmetry is x=5 
charle [14.2K]4 years ago
4 0

Answer: X=5

Step-by-step explanation:

i took the test on FLVS

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Solve 5y^2+20=80, where y is the real number
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Step-by-step explanation:

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40x=10x^2+41 <br><br> Identify the number of solutions and their types using the discriminant
nydimaria [60]

Number of solutions: no roots

Type of solution: Not Real

Step-by-step explanation:

We need to identify the number of solutions and their types using the discriminant.

We are given: 40x=10x^2+41\\

Rearranging:

40x-10x^2-41=0\\10x^2-40x+41=0

Discriminant can be found by: b^2-4ac

where b=-40, a=10 and c=41

Putting values:

b^2-4ac\\=(-40)^2-4(10)(41)\\=1600-1640\\=-40\\

So, Discriminant is -40

If the discriminant is less than zero i.e -40 then there are no real roots.

So, Number of solutions: no roots

Type of solution: Not Real

Keywords: discriminant

Learn more about discriminant at:

  • brainly.com/question/8196933
  • brainly.com/question/9328925
  • brainly.com/question/9184197

#learnwithBrainly

6 0
3 years ago
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