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-Dominant- [34]
3 years ago
9

good morning fellow brainsters please help me i’m tired and i just drank a four loko... can’t think. will give 15 points

Mathematics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

7. x=3

8. l=11cm and w=7 cm

9. x-5\ge12

10. \frac{x}{3}\le15

Step-by-step explanation:

Question 7.

The given expression is:

12-3(2x+1)=7x-3(7+x)

Expand the parenthesis using the distributive property:

12-6x-3=7x-21-3x

Group similar terms:

-6x-7x+3x=-21+3-12

Simplify

-10x=-30

Divide both sides by -10

x=3

Question 8:

Let the width of the rectangle be; w

The length of the rectangle is l=w+4

The perimeter is given as: P=2(l+w)

Given that the perimeter P=36, then:

36=2[(w+4)+w)]

\implies 36=2(2w+4)

Divide both sides by 2:

\implies 18=2w+4

Subtract 4 from both sides:

\implies 18-4=2w

\implies 14=2w

\implies w=7

The dimensions of the rectangle is: w=7 cm and l=7+4=11cm

Question 9

Let the number be x.

"5 fewer than the number" is written as x-5

"5 fewer than a number is at least 12" becomes

x-5\ge12

Question 10:

Let the number be x.

The quotient of a number and 3 is written as:

\frac{x}{3}

The quotient of a number and 3 is no more than 15 is written as;

\frac{x}{3}\le15

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Answer:

Mean = 28.33

Step-by-step explanation:

Comment

You need two inputs. The first is the sum of the numbers and the second is the number of entries in the data.

Givens

Sum = 3 +  32 +   36 +   30 +   33 +   36

Number of entries = 6

Solution

Sum = 170

Mean = sum / number of enteries

Mean = 170 / 6

Mean = 28.33

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(05.08) Solve for x: 2 over quantity x minus 2 plus 7 over quantity x squared minus 4 equals 5 over x. (2 points) x = negative 4
Oxana [17]

Answer:

Step-by-step explanation:

The best way to do this is to use your LCM and eliminate the fractions.  To find the LCM you have to use all the denominators as a multiplier so the denominator in each term cancels out.  We will first factor the x-squared term to simplify and see what 2 factors are hidden there.

x^2-4 factors to (x + 2)(x - 2).  That means that our 3 denominators that make up our LCM are x(x+2)(x-2).  We will mulitply that in to each term in our rational equation, canceling out the denominators where applicable.

x(x+2)(x-2)[\frac{2}{(x-2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}]

In the first term, the (x-2) will cancel leaving us with

x(x+2)[2] which simplifies to

x^2+2x[2]

In the second term, the (x+2)(x-2) cancels out leaving us with

x[7].

In the last term, the x cancels out leaving us with

(x+2)(x-2)[5] which simplifies to

x^2-4[5]

Now we will distribute through each cancellation:

2x²+4x;

7x;

5x²-20

Putting them all together we have

2x² + 4x + 7x = 5x² - 20

Combining like terms gives us a quadratic:

3x² - 11x - 20 = 0

Factor that however you find it easiest to factor quadratics and get that

x = 5 and x = -4/3

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3 years ago
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