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3 years ago

What is the percent of 330

Mathematics

1 answer:

Vesna [10]3 years ago

7 0

33,000% should be the answer

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Mr. Cornapple is the fruit & vegetable buyer for a large school district. In a given week, he has a budget of $6,550. Bushel

Nina [5.8K]

Answer:

40x + 30y ≤ 6,550

Step-by-step explanation:

Given:

Cost of each apple bushels = $40

Cost of each corn bushels = $30

Total budget = $6,550

Find:

Inequality

Computation:

Assume;

Total number of apple bushels = x

Total number of corn bushels = y

So,

40x + 30y ≤ 6,550

6 0

3 years ago

The city is replacing all the streets, curbs, and gutters in Middleville. The homeowners on both sides of the street are charged

bija089 [108]

Mr. Kyle will be expected to pay $8,100.

The total cost for his land would be 120 x 90 = 10,800.

Since the city is paying 25%, he must pay the other 75%.

0.75 x 10800 = 8100

8 0

3 years ago

Given parallelogram ABCD , diagonals AC and BD intersect at point E. AE=2x, BE=y+10, CE=x+2 and DE=4y−8 . Find the length of AC

Crank

Answer:

I think the answer shod be B

3 0

3 years ago

How to write 1/4 as a decimal

Gnom [1K]

Answer:

0.25

Step-by-step explanation:

As a decimal, 0.25

As a fraction, 1/4

As a percentage, 25%

3 0

3 years ago

Read 2 more answers

A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long

Pie

Answer:

Surface area of pyramid with base equilateral triangle is $390+100\sqrt{3}$ square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

$S = \frac{1}{2}pl+B$ ...... (1)

Here, p represents the perimeter of the base , $l$ the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid( $l$ ) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = $3 \times (side)$

= $3 \times 20 = 60 inches$

Area of equilateral triangle(B) = $\frac{\sqrt{3} }{4} \times (side)^{2}$

= $\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}$ square inches.

Substitute the above values in equation (1) as shown below:

$S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}$

$S= 390+100\sqrt{3}$ square inches

Hence, the surface area of pyramid with base equilateral triangle is $390+100\sqrt{3}$ square inches.

6 0

2 years ago