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lisov135 [29]
3 years ago
10

1. A candy store sells chocolate bars for $2.25 each, lollipops for $1.00 each, and bags of individually wrapped candy for $4.00

each.
Answer question 1C please

Mathematics
2 answers:
OLEGan [10]3 years ago
6 0

Answer:i dont know how much the candy store bought the stuff for but this is how much they sold 4 chocolate bars, 10 lollipops, and 4 bags of candy for. subtract that from the amount of money spent to buy/make the cnady and that will be your answer

$35

Step-by-step explanation:

4(2.25)+10(1.00)+4(4.00)=35

Veseljchak [2.6K]3 years ago
5 0

Answer:

$35

Step-by-step explanation:

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Answer: 1692

Step-by-step explanation:

Formula to find the sample size :

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2

Given : Confidence level : (1-\alpha)=0.90

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z-value for 90% confidence interval (using z-table)=z_{\alpha/2}=1.645

Prior estimate of the population proportion (p) of customers who keep up with regular vehicle maintenance is unknown.

Let we take p= 0.5

Margin of error : E= 2%=0.02

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n=0.5(1-0.5)(\dfrac{1.645}{0.02})^2

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<u>ANSWER:  </u>

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<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

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\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

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4 0
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