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allsm [11]
3 years ago
6

Which number is multiple of 17? A) 32 B) 48 C) 57 D) 85

Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0

Answer:

<em><u>D)85</u></em>

Step-by-step explanation:

The right answer would be an equal number so here is the work

32 divided by 17= 1.882352941

48 divided by 17=2.823529412

57 divided by 17=3.352941176

<em><u>85 divided by 17=5</u></em>

xeze [42]3 years ago
5 0

Answer:

D) 85.

Step-by-step explanation:

5 times 17 = 85.

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175140 is the LCM of 2 085 and 252

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100 Points<br><br>Which angle is the angle of incident?
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angle c

Step-by-step explanation:

angle c is the angle of incidence.  It is the angle between the perpendicular  ( line that meets the surface at 90 degrees) and the ray that is coming in

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Help please let me know if I’m wrong or right pls!!!!
Ksju [112]

Answer:

you are correct! nonlinear

Step-by-step explanation:

when this equation is graphed it forms a curved line-- making it non linear :)

4 0
3 years ago
Pregnant women metabolize some drugs at a slower rate than the rest of the population. The half-life of caffeine is about 4 hour
UkoKoshka [18]

Answer:

Husband:

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Woman:

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

Step-by-step explanation:

The amount of caffeine in the body can be modeled by the following equation:

C(t) = C(0)e^{rt}

In which C(t) is the amount of caffeine t hours after 8 am, C(0) is how much coffee they took and r is the rate the the amount of caffeine decreases in their bodies.

110 mg of caffeine at 8 am,

So C(0) = 110

Husband

Half life of 4 hours. So

C(4) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{4r}

e^{4r} = 0.5

Applying ln to both sides

\ln{e^{4r}} = \ln{0.5}

4r = \ln{0.5}

r = \frac{\ln{0.5}}{4}

r = -0.1733

So for the husband

C(t) = 110e^{-0.1733t}

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.1733t}

C(11) = 110e^{-0.1733*11} = 16.35

The husband will have 16.35 mg of caffeine in his body at 7 pm.

Pregnant woman

Half life of 10 hours. So

C(10) = 0.5C(0) = 0.5*110 = 55

C(t) = C(0)e^{rt}

55 = 110e^{10}

e^{10r} = 0.5

Applying ln to both sides

\ln{e^{10r}} = \ln{0.5}

10r = \ln{0.5}

r = \frac{\ln{0.5}}{10}

r = -0.0693

At 7 pm

7 pm is 11 hours after 8 am, so this is C(11)

C(t) = 110e^{-0.0693t}

C(11) = 110e^{-0.0693*11} = 51.33

The pregnant woman will have 51.33 mg of caffeine in her body at 7 pm.

7 0
4 years ago
BRAINLIEST IF CORRECT
stellarik [79]
The answer is C. f(x) = 0.05 
4 0
3 years ago
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