There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
Answer:
Step-by-step explanation:
hypotenuse
Answer:
5
Step-by-step explanation:
Substitute 2 in for x
|2+3| = 5
This would take the absolute value of the answer, or in other words once you solve the equation it will remove any negatives to return a positive number. I took the test and I have links to prove it.
Answer:
9+10 =19
Step-by-step explanation:is that wat u wanted
