Solve the system using substitution. Show all work.

Determine if this data is an example

tankabanditka [31]

Answer:

Step-by-step explanation:

it is not a function because -2 has two y values

6 0

3 years ago

Each side of a pentagon is 10 cm greater than the previous side. If the perimeter of this pentagon is 500 cm, find the lengths o

Vesna [10]

Answer: See explanation

Step-by-step explanation:

The perimeter of a pentagon is gotten through the summation of its five sides. Let the first side be represented by x. Since each side of a pentagon is 10 cm greater than the previous side, then the sides will be:

First side = x

Second side = x + 10

Third side = x + 10 + 10 = x + 20

Forth side = x + 30

Fifty side = x + 40

Therefore,

x + (x + 10) + (x + 20) + (x + 30) + (x + 40) = 500

5x + 100 = 500

5x = 500 - 100

5x = 400

x = 400/5

x = 80

Therefore, the lengths will be:

First side = x = 80cm

Second side = x + 10 = 80 + 10 = 90cm

Third side = x + 20 = 80 + 20 = 100cm

Forth side = x + 30 = 80 + 30 = 110cm

Fifty side = x + 40 = 80 + 40 = 120cm

8 0

2 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

What does "As Much" mean in math? I am doing homework and I don't want to fail so I really need help.

igor_vitrenko [27]

It means the same used in a question like this, is 25 as much as 25.

4 0

3 years ago

Please help! I need the surface area for both. Absurd answer are not tolerated. Thanks if you help!

Natasha_Volkova [10]

Answer:

<h3>Figure 1</h3>

Perimeter of base = 5 + 5 + 8 = 18 ft

Height = 7 ft

Base area = 1/2(8)(3) = 12 ft²

<u>Surface area:</u>

S = 18*7 + 2*12 = 150 ft²

<h3>Figure 2</h3>

<u>Surface area of cube:</u>

S = 6a² = 6(2.5)² = 37.5 m²

<u>Surface area of prism:</u>

S = 2(11 + 9)(7) = 280 m²

<u>Overlapping area:</u>

S = 2.5² = 6.25 m²

<u>Surface area of composite figure:</u>

S = 280 + 37.5 - 2(6.25) = 305 m²

4 0

3 years ago