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romanna [79]
3 years ago
11

2. If I have 45 g of Carbon, to find the number of moles of carbon I would *

Chemistry
2 answers:
pshichka [43]3 years ago
4 0

Answer:

3.35 moles.

Explanation:

Sati [7]3 years ago
3 0

Answer:

divide by molar mass (12.01 g)

Explanation:

To find the number of moles of the carbon, divide by molar mass (12.01 g).

The number of moles of a substance is given as;

           Number of moles  = \frac{mass}{molar mass}

To solve this problem;

  since mass of carbon  = 45g

                Number of moles  = \frac{45}{12.01}   = 3.75moles

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Answer:

From the Online Catalog to the Shelf

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Explanation:

5 0
3 years ago
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Calculate ΔS° for the reaction: 4Cr(s) + 3O2(g) → 2Cr2O3(s), Substance: Cr(s) O2(g) Cr2O3(s), S°(J/K⋅mol): 23.77 205.138 81.2
Mariana [72]

<u>Answer:</u> The value of \Delta S^o for the reaction is 1051.93 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

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The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cr_2O_3(s))})]-[(4\times \Delta S^o_{(Cr(s))})+(3\times \Delta S^o_{(O_2(g))})]

We are given:

\Delta S^o_{(Cr_2O_3(s))}=881.2J/K.mol\\\Delta S^o_{(O_2(g))}=205.13J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (881.2))]-[(4\times (23.77))+(3\times (205.13))]\\\\\Delta S^o_{rxn}=1051.93J/K

Hence, the value of \Delta S^o for the reaction is 1051.93 J/K

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4 years ago
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3 years ago
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igomit [66]

Answer: c 3

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