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3 years ago

10

write one way or representing the equation of the given line in point-slope form. then write the equation in slope-intercept for

m. (-2,4) (1,-1)

1 answer:

ehidna [41]3 years ago

5 0

Answer:

$y + 1 =-\frac{5}{3}(x-1)$

$y = -\frac{5}{3}x + \frac{2}{3}$

Step-by-step explanation:

To write the equation of a line you need a point and a slope. Use the two points given to find the slope.

$m = \frac{-1 - 4}{1--2} = \frac{-5}{3}$

Substitute m = -5/3 and the point (1,-1) into the point slope form.

$y - y_1 = m(x-x_1)\\y --1 = -\frac{5}{3}(x-1)\\y + 1 =-\frac{5}{3}(x-1)$

Use the distributive property to convert to slope intercept form.

$y + 1 = -\frac{5}{3}x + \frac{5}{3}\\y = -\frac{5}{3}x + \frac{5}{3} - 1\\y = -\frac{5}{3}x + \frac{2}{3}$

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A coordinate plane with a line drawn passing through the points (0, 3) and (3, 2).

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None of the equations given is the equation of the function. The correct equation is: $y=-\frac{x}{3}+3\\$

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First we must find the slope of the line that passes through these points.

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In this case since we have the points: $(0, 3)$ and $(3, 2).$

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4 years ago

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Let R be the region bounded by

loris [4]

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$\displaystyle \int_1^2 (x + 6) - 7\sin\left(\dfrac{\pi x}2\right) \, dx + \int_2^{22/7} (x+6) - 7(x-2)^2 \, dx \approx 9.36$

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