What is [(x^2y^3)^1/3]/ [^3 √x^2y] in exponential form?
2 answers:
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Given:
No of users in February is 45,000 and in october its 60,000.
t=2
Therefore, approximate no of users after 2 years is 106667.
Given:
No of users in February is 45,000 and in october its 60,000.
t=2
Therefore, approximate no of users after 2 years is 106667.