The product of one term of a multiplicand and one term of its multiplier
Answer:
3(x + 2)(2x - 5)
Step-by-step explanation:
Given
6x² - 3x - 30 ← factor out 3 from each term
= 3(2x² - x - 10) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 2 × - 10 = - 20 and sum = - 1
The factors are + 4 and - 5
Use these factors to split the x- term
2x² + 4x - 5x - 10 ( factor the first/second and third/fourth terms )
= 2x(x + 2) - 5(x + 2) ← factor out (x + 2) from each term
= (x + 2)(2x - 5), thus
2x² - x - 10 = (x + 2)(2x - 5) and
6x² - 3x - 30
= 3(x + 2)(2x - 5) ← in factored form
Answer:
36
Step-by-step explanation:
AB + BC = AC
4m - 15 + 5m - 6 = 15
m - 21 = 15
m = 36
1. Convert percent into decimal (it will help)
2. Convert Decimal to fraction
Answer:
∠ B = 85°
Step-by-step explanation:
Complementary angles sum to 90° , then
x - 23 + 2x + 29 = 90 , that is
3x + 6 = 90 ( subtract 6 from both sides )
3x = 84 ( divide both sides by 3 )
x = 28
Then
∠ B = 2x + 29 = 2(28) + 29 = 56 + 29 = 85°
