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Crazy boy [7]
3 years ago
10

two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat

ion in 32 minutes. Car B travels 5 miles farther than car A. How fast do the cars travel?​
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
3 0

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : v=\frac{distance}{time}. Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

v\,*\,24\,min=d_A

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

v\,*\,32\,min=d_A+5\,miles

Now we solve for d_A in this last equation and make the substitution in the equation for car A:

v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}

So this is the speed of both cars: 0.625 miles/minute

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4 0
3 years ago
A chemist has three different acid solutions. The first acid solution contains 25 % acid, the second contains 45 % and the third
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Answer:

Wyzant

ALGEBRA WORD PROBLEM

Dorian S. asked • 06/28/17

THREE LINEAR EQUATIONS WITH THREE VARIABLES

A chemist has three different acid solutions. The first acid solution contains 15% acid, the second contains 25%,

and the third contains 70%. He wants to use all three solutions to obtain a mixture of 40 liters containing 45%

acid, using 2 times as much of the 70% solution as the 25% solution. How many liters of each solution should be used?

How to set up as three linear equations to find the answer?

Follow2

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1 Expert Answer

By:

Best

Arthur D. answered • 06/28/17

TUTOR 4.9 (67)

Forty Year Educator: Classroom, Summer School, Substitute, Tutor

ABOUT THIS TUTOR ›

set up 2 equations

the first equation...

15%*x+25%*y+70%*2y=45%*40

0.15x+0.25y+1.4y=0.45*40

0.15x+1.65y=18

multiply all terms by 100

15x+165y=1800

divide all terms by 15

x+11y=120

the second equation...

x+y+2y=40

x+3y=40

x=40-3y

substitute into the first equation x+11y=120

40-3y+11y=120

40+8y=120

8y=120-40

8y=80

y=80/8

y=10 liters

x+3*10=40

x+30=40

x=40-30

x=10 liters

10 liters of 15%, 10 liters of 25%, and 20 liters of 70%

check:

10*15%=1.5

10*25%=2.5

20*70%=14

1.5+2.5+14=18

18/40=9/20=45/100=45%

45%*40=18

hope it helps

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