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kobusy [5.1K]
3 years ago
13

Please show how to solve! 3(x+2)^3/5 +3=27

Mathematics
1 answer:
padilas [110]3 years ago
6 0

Answer:

x=30

Step-by-step explanation:

3(x+2)^3/5 +3=27

Subtract 3 from each side

3(x+2)^3/5 +3-3=27-3

3(x+2)^3/5 =24

Divide by 3

3/3(x+2)^3/5 =24/3

(x+2)^3/5 =8

Take everything to the 5/3 power to get rid of the exponent on the left side

(x+2)^3/5 ^ 5/3=8 ^ 5/3

Remember that a^b^c = a^ (b*c)

(x+2)^(3/5 * 5/3)=8 ^ 5/3

(x+2)=8 ^ 5/3

Replace 8 with 2^3

(x+2)=2^3 ^ 5/3

Remember that a^b^c = a^ (b*c)

(x+2)=2^(3 * 5/3)

x+2 = 2^5

x+2 = 32

Subtract 2 from each side

x+2-2 = 32-2

x=30

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

In this question, we are tasked with calculating the probability that out of two cards drawn with replacement from a pack of cards , at least one of the two is a face card.

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Now let’s calculate the number of face cards we have.

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Now, we want to calculate the probability of at least one of the cards drawn are face cards.

Mathematically, what we are needing to calculate is

Probability of drawing a single face card or probability of the two being a face card

Now let’s calculate.

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