Please show how to solve! 3(x+2)^3/5 +3=27

Mathematics

1 answer:

padilas [110]3 years ago

6 0

Answer:

x=30

Step-by-step explanation:

3(x+2)^3/5 +3=27

Subtract 3 from each side

3(x+2)^3/5 +3-3=27-3

3(x+2)^3/5 =24

Divide by 3

3/3(x+2)^3/5 =24/3

(x+2)^3/5 =8

Take everything to the 5/3 power to get rid of the exponent on the left side

(x+2)^3/5 ^ 5/3=8 ^ 5/3

Remember that a^b^c = a^ (b*c)

(x+2)^(3/5 * 5/3)=8 ^ 5/3

(x+2)=8 ^ 5/3

Replace 8 with 2^3

(x+2)=2^3 ^ 5/3

Remember that a^b^c = a^ (b*c)

(x+2)=2^(3 * 5/3)

x+2 = 2^5

x+2 = 32

Subtract 2 from each side

x+2-2 = 32-2

x=30

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