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alina1380 [7]
3 years ago
8

Describe three ways that urbanization could affect land and aquatic ecosystems around cities.

Biology
1 answer:
aalyn [17]3 years ago
3 0

It causes pollution

It can cause loss of life

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Put the phases of the earth's atmosphere and their causes in order
Temka [501]

Answer:

Explanation:

All great elements

4 0
3 years ago
If 57.9 grams of gold has a volume of 3 cubic centimeters, what is the density of gold in g/cm3
tatiyna
It is 19.3g/cm^3. To find density, you divide mass by volume, or d=m/v
3 0
4 years ago
There is a population of alien dogs, species Dogus Cute-ee-us, that live on the planet Woof. Their genomes and biology are amazi
kupik [55]

Answer:

c. 1:4:6:4:1

Explanation:

The term quantitative heritability refers to the transmission of a phenotypic trait in which expression depends on the additive effect of a series of genes.  

Polygenic heritability occurs when a trait results from the interaction of more than one gene. And these genes can also have more than two alleles. The action of many genes and alleles can cause many different combinations that are the reason for genotypic graduation.  

Quantitative traits are those that can be measure, such as longitude, weight, eggs laid per female, among others. In the exposed example, the measurable trait is the dog´s friendliness. These characters do not group individuals by any precise and clear categories. Instead, they group individuals in many different categories that depend on how the genes were intercrossed and distributed during meiosis. The result depends on the magnitude in which each allele contributes to the final phenotype and genotype. When they interact, they create a gradation in phenotypes, according to the level of contribution.  

In the exposed example, each dominant allele contributes with a higher level of friendliness.    

  • aabb → 0 = Unfriendly/Loner (although not aggressive);
  • Aabb, aaBb → 1 = Somewhat friendly/shy;
  • AAbb, AaBb, aaBB → 2 = Friendly;
  • AABb, aABB → 3 = Very friendly;
  • AABB → 4 = Maximally friendly.

Cross: between two dihybrid friendly dogs

Parentals) AaBb    x    AaBb

Gametes) AB, Ab, aB, ab

                AB, Ab, aB, ab

Punnett square)   AB       Ab       aB       ab

                   AB   AABB   AABb  AaBB  AaBb

                    Ab   AABb    AAbb  AaBb  Aabb

                    aB   AaBB    AaBb   aaBB   aaBb

                    ab    AaBb    Aabb   aaBb   aabb

F1) 1/16 AABB ⇒ 4 = Maximally friendly

    4/16 AABb + AaBB ⇒ 3 = Very friendly

    6/16 AAbb + AaBb + aaBB ⇒ 2 = Friendly

    4/16 Aabb + aaBb ⇒ 1 = Somewhat friendly/shy

    1/16 aabb ⇒ 0 = Unfriendly/Loner

The Phenotypic ratio is 1:4:6:4:1

   

6 0
3 years ago
A phenotypically normal couple has a colorblind klinefelter son (xxy). In which parent and at what meiotic stage must the non-di
ad-work [718]

Answer;

D. Meiosis ii of mother

Explanation;

-The non-disjunction occurs in the meiosis II of the mother. This non-disjunction occurs when the two sister chromatids X and X fails to separate during meiosis II and produces an egg having two X chromosomes.

-Klinefelter syndrome is a condition that occurs in males when they have an extra X chromosome. The syndrome is not inherited, but usually occurs as a random event during the formation of reproductive cells (eggs and sperm) that results in the presence of one extra copy of the X chromosome in each cell (47,XXY).

4 0
4 years ago
what compound is the major precursor to all glycerophospholipids? what compound is the major precursor to all glycerophospholipi
d1i1m1o1n [39]

Acetyl call age is the major precursor to all glycerophospholipids.

<h3>What is glycerophospholipids?</h3>

Glycerophospholipids are detergents and, as such, they reduce water surface tension and stabilize the dispersion of hydrophobic compounds (cholesterol and neutral fats) in aqueous solutions. The capacity of phospholipids to function as detergents is important in bile, where they favor the solubility of cholesterol.

in the given question, this is part of the concept of a cycle basically in biology. So this compound is not considered a precursor for the production of glucose neurogenesis in humans, which is the correct answer, we have the Acetyl Call Age. The reason is that always remember that the gluconate eugenic pathway converts pyre of eight two glucose and non-carbohydrate precursors of glucose are first converted into paraguay or even in the pathway at later intermediates such as axel acetate and the hydro accident phosphate, the main non-carbohydrate precursor, our lactate, we have lock band, we have amino acids and also glycerol. In the human body, glucose cannot be synthesized from fatty acids because they are converted by beta-oxidation to acetyl coenzyme, which then enters the citric acid cycle where it is oxidized to carbon dioxide. The starting materials for glucose neurogenesis. Our three carbon compounds including lactate pyre of it and we also have glycerol and certain amino acids, fatty acids and ketogenic amino acids cannot be used to synthesize glucose. The transition reaction is a one-way reaction, which means that the acid still cannot be converted back to piracy. Consequently, fatty acids cannot be used to synthesize glucose because better oxidation will produce acidic alkalis. Acetylcola is therefore not considered a precursor for the production of glucose.

To learn more about glycerophospholipids from the given link:

brainly.com/question/23105733

#SPJ9

8 0
1 year ago
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