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Yanka [14]
3 years ago
7

Which product is negative?

Mathematics
2 answers:
bazaltina [42]3 years ago
8 0

For this case we have that by definition, the law of the signs of multiplication states that:

+ * + = +\\+ * - = -\\- * + = -\\- * - = +

So:

<em>Option A: </em>

- * - * + = + * + = +

It does not give a negative sign.

<em>Option B: </em>

+ * - * - = - * - = +

It does not give a negative sign.

<em>Option C: </em>

+ * + * + = + * + = +

It does not give a negative sign.

<em>Option D: </em>

- * - * - = + * - = -

The sign is negative.

Answer:

Option D

GREYUIT [131]3 years ago
5 0

Answer: The Last One

Step-by-step explanation: The Last One Would Be A Product Of Negative

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A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A
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Answer:

a) -13.9 ft/s

b) 13.9 ft/s

Step-by-step explanation:

a) The rate of his distance from the second base when he is halfway to first base can be found by differentiating the following Pythagorean theorem equation respect t:

D^{2} = (90 - x)^{2} + 90^{2}   (1)

\frac{d(D^{2})}{dt} = \frac{d(90 - x)^{2} + 90^{2})}{dt}

2D\frac{d(D)}{dt} = \frac{d((90 - x)^{2})}{dt}  

D\frac{d(D)}{dt} = -(90 - x) \frac{dx}{dt}   (2)

Since:

D = \sqrt{(90 -x)^{2} + 90^{2}}

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D = \sqrt{(90 - 45)^{2} + 90^{2}} = 100. 62

Now, by introducing D = 100.62, x = 45 and dx/dt = 31 into equation (2) we have:

100.62 \frac{d(D)}{dt} = -(90 - 45)*31          

\frac{d(D)}{dt} = -\frac{(90 - 45)*31}{100.62} = -13.9 ft/s

Hence, the rate of his distance from second base decreasing when he is halfway to first base is -13.9 ft/s.

b) The rate of his distance from third base increasing at the same moment is given by differentiating the folowing Pythagorean theorem equation respect t:

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\frac{d(D^{2})}{dt} = \frac{d(90^{2} + x^{2})}{dt}

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We have that D is:

D = \sqrt{x^{2} + 90^{2}} = \sqrt{(45)^{2} + 90^{2}} = 100.63

By entering x = 45, dx/dt = 31 and D = 100.63 into equation (3) we have:

\frac{dD}{dt} = \frac{45*31}{100.63} = 13.9 ft/s

Therefore, the rate of the batter when he is from third base increasing at the same moment is 13.9 ft/s.

I hope it helps you!

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3 years ago
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