Question

Is the given function phi(x) = x^2 - x^-1 an explicit solution to the linear equation d^2y/dx^2 - 2/x^2 y = 0? Circle your answer. (a) yes (b) no

Answer 1

Answer:

Yes

Step-by-step explanation:

We are given that a function $\phi(x)=x^2-x^{-1}$

We have to find that given function is an explicit solution to the linear equation

$\frac{d^2y}{dx^2}-\frac{2}{x^2}y=0$

If given function is an explicit solution of given linear equation then it satisfied the given differential equation

Differentiate w.r.t x

Then we get $\phi'(x)=2x+x^{-2}$

Again differentiate w.r.t x

Then we get

$\phi''(x)=2-\frac{2}{x^3}$

Substitute all values in the given differential equation

$2-\frac{2}{x^3}-\frac{2}{x^2}(x^2-x^{-1})$

=$2-\frac{2}{x^3}-2+\frac{2}{x^3}=0$

Hence, given function is an explicit solution of given differential equation.

Therefore, answer is yes.