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Mkey [24]
3 years ago
12

Alternate interior angles

Mathematics
1 answer:
FromTheMoon [43]3 years ago
3 0
Angle 3 and 5 are alternate interior angles, please mark me Brainliest!
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Miley has a shoe shelf 33 inches wide. if each of her shoes is 2 3/4 inches wide how many shoes can she fit on the shelf?​
Ksivusya [100]

Answer:

12 shoes

Step-by-step explanation:

Divide 33 by 2 3/4

4 0
3 years ago
Read 2 more answers
Find the x-intercepts of the parabola with vertex (-4,2) and y-intercept (0,-30). Write your answer in this form: (x1, y1),(x2,
Ainat [17]
Vertex form of a parabola 
<span>y = a (x - h)^2 + k </span>

<span>where (h, k) is the vertex </span>
Substituting the values of h and k.
we get, 

<span>y = a(x + 4)^2 + 2 </span>

<span>substituting in the point (0, -30) for  x and  y
</span><span>-30 = a (0 + 4)^2 + 2 

</span>solve for a,

<span>-30 = 16 a + 2 </span>
<span>-32 = 16 a </span>
<span>-2 = a </span>

<span>y = -2(x + 4)^2 + 2 </span>

<span>Put y = 0 </span>

<span>-2 x^2 - 16 x - 30 = 0 </span>
<span>-2(x^2 + 8 x + 15) = 0 </span>
<span>x^2 + 8 x + 15 = 0 </span>
<span>(x + 3)(x + 5) = 0 </span>

<span>x = -3
x = -5</span>
3 0
3 years ago
Two fair six-sided dice are rolled.
sladkih [1.3K]
1/36+1/36=2/36. why? because their are 6 sides. you must multiply. and for each dice ylu have a possibilty of 1/36.
5 0
3 years ago
How many and what type of solutions does the equation have?
Oxana [17]
Here's how one would solve it:

17 + 3x2 = 6x
17 + 6 = 6x
23 = 6x
x = 23/6

There's only one solution.
8 0
3 years ago
A bag contains 4 white,5 blacks and 2 blue balls. 3 balls are drawn one after the other without replacement from the bag .what i
Doss [256]

Answer:

24/99

Step-by-step explanation:

From the question given above, the following data were obtained:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

Probability that they are of different color =?

Next, we shall determine the total number of balls in the bag. This can be obtained as follow:

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 4 + 5 + 2 = 11 balls

Next, we shall determine the possible outcome of draw. This can be obtained as follow.

The possible outcome could be:

WBLB or WBBL or BBLW or BWBL or BLBW or BLWB

Next we shall determine the probability of each of outcomes.

Since the ball is drawn without replacement, it means the total number of ball will reduce after each draw.

White (W) balls = 4

Black (B) balls = 5

Blue (Bl) balls = 2

TOTAL = 11

P(WBLB) = 4/11 × 2/10 × 5/9 = 40/990

P(WBLB) = 4/99

P(WBBL) = 4/11 × 5/10 × 2/9 = 40/990

P(WBBL) = 4/99

P(BBLW) = 5/11 × 2/10 × 4/9 = 40/990

P(BBLW) = 4/99

P(BWBL) = 5/11 × 4/10 × 2/9 = 40/990

P(BWBL) = 4/99

P(BLBW) = 2/11 × 5/10 × 4/9 = 40/990

P(BLBW) = 4/99

P(BLWB) = 2/11 × 4/10 × 5/9 = 40/990

P(BLWB) = 4/99

Finally, we shall determine the probability that they are of different color. This can be obtained as follow:

P(WBLB) = 4/99

P(WBBL) = 4/99

P(BBLW) = 4/99

P(BWBL) = 4/99

P(BLBW) = 4/99

P(BLWB) = 4/99

Probability that they are of different color =?

Probability that they are of different color = P(WBLB) + P(WBBL) + P(BBLW) + P(BWBL) + P(BLBW) + P(BLWB)

= 4/99 + 4/99 + 4/99 + 4/99 + 4/99 + 4/99

= (4 + 4 + 4 + 4 + 4 + 4)/99

= 24/99

Thus, the probability that they are of different color is 24/99

4 0
3 years ago
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