Answer:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
A particular employee arrives at work sometime between 8:00 a.m. and 8:30 a.m.
We can consider 8 am = 0, and 8:30 am = 30, so 
Find the probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Between 15 and 25, so:
0.3333 = 33.33% probability that the employee will arrive between 8:15 a.m. and 8:25 a.m.
Answer:
1) 4 2)7
Step-by-step explanation:
1) If we divide 3.75/3=1.25 which is the amount of time she takes per yard so if we add another yard to what she has already done we find she only could do one more yard in 5 hours 3.75+1.25=5.00 So she can only rake 4 yards in 5 hours
2) If we divide 20.25/3=6.75 we find that each ticket is $6.75 so we must divide that by 47.25 to get the amount of tickets 47.25/6.75=7
Answer:
3y -- 6
Step-by-step explanation:
if the largest number is y, then the other two integers would be (y -- 2) and (y -- 4).
Therefore the sum of the integers would be
y + (y -- 2) + (y -- 4) = 3y -- 6.
First, let's find g(4). After we find it, we can substitute the value into 
.
To find g(4), we need to substitute x = 4 into the function 
, as shown below:
Now that we have found g(4) = 9, we can substitute this value in for 
in .
f(g(4)) is equal to 28.
Answer:
The area of the house is A. 1,108
