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3 years ago

Construct a line that is tangent to a circle at a given point

1 answer:

6 0

Steps:

1) Draw the circle and mark the center (A) and the given point (B)

2) Draw a line that passes through the center (A) and the given poiint (B).

3) Draw a perpendicular line to the segment AB.

The last line drawn is tangent to the circle at the given point.

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Help please?? <br><br>Answer:

Sveta_85 [38]

1. Yes, a regular hexagon can be drawn using rotations.
2.To find the answer, first find the number of sides of a hexagon. A hexagon has six sides.
Divide 360 by 6 = 360/6=60 degrees.
So the angle of rotation for a point on the circle for drawing a regular hexagon is 60 degrees.

3 0

3 years ago

A die is rolled 3 times. What is the probability of getting 1’s on each roll?

meriva

Answer: The answer is around 16.66%

4 0

3 years ago

Read 2 more answers

Let x be the amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train. Suppose that the d

larisa [96]

Answer:

a) $P(X$

$P(X>14) = 1-P(X$

b) $P(7< X$

c) We want to find a value c who satisfy this condition:

$P(x$

And using the cumulative distribution function we have this:

$P(x$

And solving for c we got:

$c = 20*0.9 = 18$

Step-by-step explanation:

For this case we define the random variable X as he amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train, and we know that the distribution for X is given by:

$X \sim Unif (a=0, b =20)$

Part a

We want this probability:

$P(X$

And for this case we can use the cumulative distribution function given by:

$F(x) = \frac{x-a}{b-a} = \frac{x-0}{20-0}= \frac{x}{20}$

And using the cumulative distribution function we got:

$P(X$

For the probability $P(X>14)$ if we use the cumulative distribution function and the complement rule we got:

$P(X>14) = 1-P(X$

Part b

We want this probability:

$P(7< X$

And using the cdf we got:

$P(7< X$

Part c

We want to find a value c who satisfy this condition:

$P(x$

And using the cumulative distribution function we have this:

$P(x$

And solving for c we got:

$c = 20*0.9 = 18$

3 0

3 years ago

( 1 0 3) + (4 1 7) The first entry of the resulting matrix is:

Mamont248 [21]

Hello!

When adding matrices you add the numbers that are in the same position

1 + 4 = 5

0 + 1 = 1

3 + 7 = 10

The answer is (5 1 10)

Hope this helps!

7 0

3 years ago

Read 2 more answers

What is the product of the two integer values for $x$ for which $|x^2 - 16|$ is a prime number?

Nana76 [90]

Answer:

-9

Step-by-step explanation:

x² -16 = (x -4)(x +4)

This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).

... For x-4 = ±1, x = 3 or 5

... For x+4 = ±1, x = -3 or -5

The values of x that are ±3 both give |x²-16| = 7, a prime.

The values of x that are ±5 both give |x²-16| = 9, not a prime.

The two values of x that are of interest are x=-3 and x=3. Their product is ...

... (-3)·(3) = -9

8 0

3 years ago