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3 years ago

Construct a line that is tangent to a circle at a given point

1 answer:

6 0

Steps:

1) Draw the circle and mark the center (A) and the given point (B)

2) Draw a line that passes through the center (A) and the given poiint (B).

3) Draw a perpendicular line to the segment AB.

The last line drawn is tangent to the circle at the given point.

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ARI

dezoksy [38]

Answer:

f(x)= 1/2x + 2

Step-by-step explanation:

3 0

3 years ago

The product of a number and -8 gives eight times the sum of that number and 36. Find that number

Viefleur [7K]

Answer:

-18

Step-by-step explanation:

Let x be our number. First we have to write our equation.

The product of a number and -8 is represented as -8x (-8 multiplied by x). Remember that 'product' signifies multiplication.

The result is eight times the sum of x and 36. This is represented as 8(x + 36). We add x and 36 first because 8 has been multiplied by the sum of those two numbers.

So our equation is:

-8x = 8(x + 36)

We can now solve for x. First, expand the bracket.

-8x = 8x + 288

Next, subtract 8x from both sides. This will give us only one term containing x, which will make it easier to solve.

-8x - 8x = 8x + 288 - 8x

-16x = 288

Divide both sides by -16

x = -18

3 0

3 years ago

(2^8 . 5-5. 19^0)-2. <br> What is the product

Dennis_Churaev [7]

Answer:The final value of the expression is 149

2^8 . 5^-5 . 19^0)^-2

using PEMDAS

this = (2^8 * 1/5^5 * 1)^-2

= (5^5 / 2^8)^2

= 5^10 / 2^16

8 0

3 years ago

The area of the shaded triangle is 5x2+3x-4. What is the area of the entire figure?

Phoenix [80]

The answer will be 2 cuz you multiply them at the answers

3 0

4 years ago

What is the quotient 4-x/x^2+5x-6 divided by x^2-11x+28/x^2+7x+6 in simplified form?

sashaice [31]

$\dfrac{4-x}{x^2+5x-6}:\dfrac{x^2-11x+28}{x^2+7x+6}=(*)$

$4-x=-(x-4)\\\\x^2+5x-6=x^2+6x-x-6=x(x+6)-1(x+6)=(x+6)(x-1)\\\\x^2-11x+28=x^2-7x-4x+28=x(x-7)-4(x-7)\\=(x-7)(x-4)\\\\x^2+7x+6=x^2+6x+x+6=x(x+6)+1(x+6)=(x+6)(x+1)\\\\(*)=\dfrac{-(x-4)}{(x+6)(x-1)}:\dfrac{(x-7)(x-4)}{(x+6)(x+1)}$
$=\dfrac{-(x-4)}{(x+6)(x-1)}\cdot\dfrac{(x+6)(x+1)}{(x-7)(x-4)}=\dfrac{-1}{x-1}\cdot\dfrac{x+1}{x-7}\\\\=-\dfrac{x+1}{x^2-7x-x+7}=-\dfrac{x+1}{x^2-8x+7}$

7 0

3 years ago