A.)
Z = kx/y where k is a constant.
32 = 16k/4
k = 128/16
k = 8
z = 8x/y
b.)
Z = 8(21)/6
Z = 28
c.)
4 = 8x/48
x = 192/8
x = 24
I cant see the link ummmmmm
Answer:
x= 12
Step-by-step explanation:
Answer:
c. 1/6
Step-by-step explanation:
I hope it helps you...
At
, you have
The trick to finding out the sign of this is to figure out between which multiples of
the value of
lies.
We know that
whenever
, and that
whenever
, where
.
We have
which is to say that
, an interval that is equivalent modulo
to the interval
.
So what we know is that
corresponds to the measure of an angle that lies in the third quadrant, where both cosine and sine are negative.
This means
, so
is decreasing when
.
Now, the second derivative has the value
Both
and
are negative, so we're essentially computing the sum of a negative number and a positive number. Given that
for
, and
for
, we can use a similar argument to establish in which half of the third quadrant the angle
lies. You'll find that the sine term is much larger, so that the second derivative is positive, which means
is concave up when
.
