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Mkey [24]
3 years ago
7

Volume of this prism ​

Mathematics
1 answer:
Lyrx [107]3 years ago
5 0

The volume is (area of cross-section) x (length) .

-- The cross-section is a triangle.  The area of a triangle is

Area = (1/2) (base) (height) .

In this one, the base is 9/4 m and the height is 3-1/3 m .

Area = (1/2) (9/4 m) (3-1/3 m)

Area = (1/2) (9/4) (10/3)

Area = 90/24 m² .

-- Volume = (area of cross-section) x (length)

Volume = (90/24 m²) x (7-1/3 m)

Volume = (90/24) x (22/3) m³

Volume = (1,980 / 72) m³

<em>Volume = 27.5 m³  </em>

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If f (x) = StartRoot one-half x minus 10 EndRoot + 3, which inequality can be used to find the domain of f(x)?
just olya [345]

The inequality that represents the domain of the function is \frac 12x - 10 \ge 0

<h3>How to determine the domain?</h3>

The function is given as:

f(x) = \sqrt{\frac 12x - 10} + 3

Set the radicand greater than or equal to 0

\frac 12x - 10 \ge 0

Multiply through by 2

x - 20 ≥ 0

Add 20 to both sides

x ≥ 20  

Hence, the domain of the function is x ≥ 20  

Read more about domain at:

brainly.com/question/1770447

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7 0
2 years ago
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Rewrite as a simplified faction
elena-s [515]
Here is the final answer
3 2/9
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3 years ago
Use the fact that 2 1/2 divide 1/8 =20 to find 2 1/2 divide 5/8
Tasya [4]

Answer:

4

Step-by-step explanation:

Given that 2\frac 1 2 \div \frac 1 8 =20

\Rightarrow \frac 5 2 \div \frac 1 8 =20

\Rightarrow \frac 5 2 \times 8 1 =20 \cdots(i)

Now, 2\frac 1 2 \div \frac 5 8 = \frac 5 2 \div \frac 5 8=\frac 5 2 \times \frac 8 5

This can be written as

\frac 5 2 \times \frac 8 5=\frac 5 2 \times \left( \frac 8 1 \times \frac 1 5\right) [as \frac 8 5=\frac 8 1 \times \frac 1 5]

=\left(\frac 5 2 \times \frac 8 1 \right)\times \frac 1 5

=20 \times \frac 1 5 [ by using equation (i)]

=4

Hence, 2\frac 1 2 \div \frac 5 8=4

7 0
2 years ago
What is the area of the figure​
svp [43]

Formula for the area of a triangle:

( Base X Height ) Divided by 2 or (B×H) ÷ 2

Formula for the area of a circle:

PI times the radius squared or PI × r^2

Area of the triangule part of this figure:

Base: 8ft. Height: 6ft

(8ft × 6ft) ÷ 2

48ft^2 ÷ 2

24ft^2

Since the circular part of the figure is a SEMICIRCLE, we are finding the area of a circle with the same radius but dividing it by 2 since thats just a half of a circle

Area of the semicricle:

Diameter: 10ft,

Therefore the radius is 5ft

(PI x 5ft^2) ÷ 2

39.2699081699 ft^2

39.27 ft^2

Now add these two areas together:

24ft^2 + 38.27ft^2 = 62.27ft^2

Hope it helps

6 0
3 years ago
PLZ help<br> What system of linear inequalities is shown in the graph?
GarryVolchara [31]

In order find the Inequalities, First we need to Find the Equations of Both the Lines.

<u>Equation of First line :</u>

It is passing through the Points (0 , 2) and (4 , 0)

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⇒ Equation of the First Line : y - 2 = \frac{-1}{2}(x)

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<u>Equation of Second Line :</u>

It is passing through the Points (1.5 , 0) and (0 , -3)

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⇒ Equation of the Second Line : y + 3 = 2x

⇒ Equation of the Second Line : 2x - y = 3

As the Shaded Area of the First Line is away from the Origin :

⇒ x + 2y ≥ 4

As the Shaded Area of the Second Line is towards the Origin and it is a Dotted line :

⇒ 2x - y < 3

So, the System of Linear Inequalities are :

⇒ x + 2y ≥ 4

⇒ 2x - y < 3

4 0
3 years ago
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