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vichka [17]
4 years ago
14

Ms. Medina asked the class to solve the equation 2(x+4)=18.

Mathematics
2 answers:
7nadin3 [17]4 years ago
4 0

Answer:

PEMDAS parentheses exponents multiplication divide add subtract....

rewona [7]4 years ago
3 0

Answer:

The distributive property

Step-by-step explanation:

He distributed 2 * x and 2 * 4 to get 2x +8

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prohojiy [21]

Answer:

  1. B) 48
  2. D) 81
  3. A) 11
  4. B) -81
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  6. C) 5
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  8. D) 11
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Step-by-step explanation:

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4 years ago
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If each month in reno had the same average rainfall as in august, what would the total number of millimeters be after 12 months
Inessa [10]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
ITS TIMED PLEASE HELP​
Lubov Fominskaja [6]

Answer:

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

Step-by-step explanation:

we know that

The equation of a vertical parabola in vertex form is equal to

f(x)=a(x-h)^{2}+k

where

a is a coefficient

(h,k) is the vertex of the parabola

If a > 0 the parabola open upward and the vertex is a minimum

If a < 0 the parabola open downward and the vertex is a maximum

In this problem

The coefficient a must be positive, because we need to find a minimum

therefore

Check the option C and the option D

Option C

we have

f(x)=\frac{1}{2}x^{2}-4x+5

Convert to vertex form

f(x)-5=\frac{1}{2}x^{2}-4x

Factor the leading coefficient

f(x)-5=\frac{1}{2}(x^{2}-8x)

f(x)-5+8=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x^{2}-8x+16)

f(x)+3=\frac{1}{2}(x-4)^{2}

f(x)=\frac{1}{2}(x-4)^{2}-3

The vertex is the point (4,-3) ( is a minimum)

therefore

The graph of the function f(x)=\frac{1}{2}x^{2}-4x+5 has a minimum located at (4,-3)

5 0
4 years ago
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