All categories

3 years ago

Help activity 1 and 2 , please i dont understand

Mathematics

2 answers:

Tamiku [17]3 years ago

4 0

Answer:

we have to factories it in both activities..

ch4aika [34]3 years ago

3 0

Answer:

Step-by-step explanation:

Activity 2:

c² - 6c - 40

Sum = -6

Product = -40

Factors= -10 , 4

c² - 6c -40 = c² - 10c - 4c - 10*4

= c(c - 10) - 4(c - 10)

= (c -10) (c -4)

e² + 10e +16

Sum = 10

Product = 16

Factors= 2 , 8

e² + 10e + 16 = e² + 2e + 8e + 2*8

= e(e + 2) + 8(e + 2)

= (e + 2)(e +8)

h² - 5h - 24

Sum = -5

Product = -24

Factors = 3 , -8

h² - 5h - 24 = h² + 3h - 8h - 3*8

= h(h + 3) - 8(h + 3)

= (h +3)(h - 8)

3x² - 5 x - 12

Sum = -5

Product = -12 * 3 = - 36

Factors = -9 , 4

3x² - 5x - 12 = 3x² - 9x + 4x - 4*3

= 3x(x - 3) + 4(x - 3)

=(x - 3) (3x + 4)

4x² + 4 x - 15

Sum = 4

Product = 4 * -15 = - 60

Factors = 10 , -6

4x² + 4x - 15 = 4x² + 10x - 6x - 3*5

=2x (2x + 5) - 3(2x +5)

= (2x + 5)(2x - 3)

You might be interested in

Ming & Elisa each improved their yards by planting rose bushes and geraniums. They bought their supplies from the same store

vodka [1.7K]

Answer:

9.26 per rose

Step-by-step explanation:

5 0

3 years ago

What comes next!T,F,S,S,M

Wittaler [7]

Answer:

E,D

Step-by-step explanation:

6 0

3 years ago

What are the answers ?

Anika [276]

If c = 8 and d = -5:

a) c - 3 = 8 - 3
= 5

b) 15 - c = 15 - 8
= 7

c) 3(c + d) = 3(8 + (-5))
= 3*3
= 9

d) 2c - 4d = 2(8) - 4(-5)
= 16 + 20
= 36

e) d - c^2 = -5 - (8)^2
= -5 - 64
= -69

f) 2d^2 + 5d = 2(-5)^2 + 5(-5)
= 50 - 25
= 25

5 0

3 years ago

Dont really understand how to do this

bija089 [108]

Answers:

$t_{10} = -22 \ \text{ and } S_{10} = -85$

========================================================

Explanation:

$t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2$

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

$t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4$

and so on. This process may take a while to reach $t_{10}$

There's a shortcut. The nth term of any arithmetic sequence is

$t_n = t_1+d(n-1)$

We plug in $t_1 = 5 \text{ and } d = -3$ and simplify

$t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8$

Then we can plug in various positive whole numbers for n to find the corresponding $t_n$ value. For example, plug in n = 2

$t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2$

which matches with the second term we found earlier. And,

$tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}$

---------------------

The notation $S_{10}$ refers to the sum of the first ten terms $t_1, t_2, \ldots, t_9, t_{10}$

We could use either the long way or the shortcut above to find all $t_1$ through $t_{10}$ . Then add those values up. Or we can take this shortcut below.

$Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}$

The sum of the first ten terms is -85

-----------------------

As a check for $S_{10}$ , here are the first ten terms:

t1 = 5
t2 = 2
t3 = -1
t4 = -4
t5 = -7
t6 = -10
t7 = -13
t8 = -16
t9 = -19
t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that $S_{10} = -85$ is correct.

6 0

2 years ago

What is the anser to the equation 2^{2x+2} = 2^{3x}

Marianna [84]

Answer: C) x = 2

2^{2x + 2} = 2^{3x}

Since both terms (above) have the same base, set the exponents to be equal:

2x + 2 = 3x (Rearrange to solve for x)

x = 2

∴ x = 2

8 0

3 years ago