Its impossible to draw a trapezoid with just three right angles.
a trapezoid has 4 sides, which means all the angles inside the trapezoid must add up to 360 degrees.
if you have just 3 right angles (90x3), you already use up 270 degrees. Leaving you with just 90 degrees left, which is also a right angle. That means, there has to be four, if you have at least 3.
Answer:
65 degrees
Step-by-step explanation:
Break the parallelogram up into two triangles. Angle E is 70 degrees and 45 degrees because of the property of equal opposite angles. So E 45 degrees Y 70 degrees and if you add the two up you get 115 degrees. There are 180 degrees in a triangle, so 180-115=65.
complementary angles add up to 90°, so therefore we know that ∡A + ∡B = 90°, and also they are in a ratio of 3:6.
![\bf \cfrac{A}{B}=\cfrac{3}{6}\implies \cfrac{A}{B}=\cfrac{1}{2}\implies 2A=\boxed{B} \\\\[-0.35em] ~\dotfill\\\\ A+B=90\implies A+\boxed{2A}=90\implies 3A=90\\\\\\ A=\cfrac{90}{3}\implies \blacktriangleright A=30 \blacktriangleleft \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 2(30)=B\implies \blacktriangleright 60=B \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7BA%7D%7BB%7D%3D%5Ccfrac%7B3%7D%7B6%7D%5Cimplies%20%5Ccfrac%7BA%7D%7BB%7D%3D%5Ccfrac%7B1%7D%7B2%7D%5Cimplies%202A%3D%5Cboxed%7BB%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A~%5Cdotfill%5C%5C%5C%5C%0AA%2BB%3D90%5Cimplies%20A%2B%5Cboxed%7B2A%7D%3D90%5Cimplies%203A%3D90%5C%5C%5C%5C%5C%5C%20A%3D%5Ccfrac%7B90%7D%7B3%7D%5Cimplies%20%5Cblacktriangleright%20A%3D30%20%5Cblacktriangleleft%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A2%2830%29%3DB%5Cimplies%20%5Cblacktriangleright%2060%3DB%20%5Cblacktriangleleft)
Answer:
Any numbers above -5 make this inequality true. Values that will make the inequality true: -4, -3, -2, -1, 0, 1...
About 17 times. Just do 69/4
