Bacteria is important because this bacteria binds hydrogen molecules with the gaseous nitrogen to form ammonia in the soil. During assimilation, or when plants take up nitrates from the soil, bacteria aid in the process with the plants in making ammonia. Animal wastes is also a major place where bacteria thrives and produces ammonia. The process in which assimilation occurs in plants, and then bacteria converts the nitrates to ammonia is called ammonification. From the conversion of ammonia to nitrites, bacteria also aids in this process called nitrification. The nitrifying bacteria mostly present in soils, oxidize ammonia into nitrites, and from nitrites to nitrates.
Finally, the process of denitrification also has bacteria present to aid in converting nitrates back into a gaseous form of nitrogen in the atmosphere.
Answer:
The purpose of the outer covering of the bird helps keep it warm and to help it fly, whilst the outer cover of the tree is to protect it from bugs.
Explanation:
Answer:
Adaptation 99.99% sure
Explanation:
I did this many times in school
In a Hardy-Weinberg population with two alleles, A and a, that are in equilibrium, the frequency of allele a is 0.2. The frequency of individuals that are heterozygous for this allele is 0.32.
<h3>Hardy Weinberg Equilibrium Principle </h3>
- A stable, idealized population's constant frequency of alleles and genotypes is described by the Hardy-Weinberg equilibrium principle.
- In a sizable population, random mating, or spontaneous mutations are necessary for Hardy-Weinberg equilibrium.
The Hardy-Weinberg equation dictates that the sum of the allele frequencies for each allele at the locus must equal 1, therefore p + q = 1. The Hardy-Weinberg equation is also written as p2 + 2pq + q2 = 1, where p is the population's frequency of the "A" allele and q is that of the "a" allele.
The homozygous genotype AA frequency is represented by p2, the homozygous genotype aa frequency by q2, and the heterozygous genotype aa frequency by 2pq in the equation.
Here, q = 0.2. Because of this, p = '1- q = 1 - 0.2 = 0.8.
The population of individuals who are heterozygous will now be 2pq, or 2 * 0.8 * 0.2 = 0.32.
Hence, This indicates that the population is heterozygous with a frequency of 0.32.
To learn more about Hardy Weinberg Principle refer to:
brainly.com/question/1365714
#SPJ4
