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BARSIC [14]
3 years ago
11

A while back, either James borrowed $12 from his friend Rita or she borrowed $12 from him, but he can’t quite remember which. Ei

ther way, he is planning to pay her back or ask that she pay him back this afternoon. If he has $42.80 in his wallet, which equation represents the amounts of money he may have after he sees Rita?
Mathematics
1 answer:
Illusion [34]3 years ago
4 0
Umm i dont know much about math but ill try... I assume it would be 42.80-12
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Timed test
marysya [2.9K]

Answer:

The correct answer should be 5,130

Step-by-step explanation:

the 3 in 513 is in the ones place, if it were ten times greater than 3 that would be 30, or a 3 in the tens place, the 3 in the number 5,130 is in the tens place, making that the correct choice

4 0
3 years ago
Can one of y’all help me with this pls
Goshia [24]

Answer:

B. 12/25

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7 0
3 years ago
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Please help with Geometry homework!!! Will give brainliest and 50 points to whoever answers first!!!
melomori [17]

Answer:

x = 42.5

Step-by-step explanation:

It is said:

If two angles are not corresponding, then they make up 180°. They are more known as supplementary angles.

So the equation is:

a + b = 180°

Substitute

x + 8 + 3 x + 2 = 180°

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4x = 180° - 10°

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6 0
3 years ago
Whats 3/z = 2/5. Please HELP!! Due in 20 minutes!!!
attashe74 [19]

Step-by-step explanation:

Hey there!!

Given,

\frac{3}{z}  =  \frac{2}{5}

Cross multiply.

15 = 2z

Therefore, z= 15/2

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
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In how many ways can the letters in the word MATHEMATICS be reshuffled so that all consonants appear together?
steposvetlana [31]

Answer:

75600

Step-by-step explanation:

We are given that  a word MATHEMATICS

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T repeated 2 times

A repeated 2 times

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Let MTHMTCS=P

Total number of ways in which MTHMTCS can be arranged=\frac{7!}{2!2!}

PAEAI

Total number of ways in which PAEAI can arranged=\frac{5!}{2!}

Total number of arrangements when all consonant appear together=\frac{7!}{2!2!}\times \frac{5!}{2!}

Total number of arrangements when all consonant appear together=\frac{7!5!}{2\times 2\times 2}=\frac{7\times 6\times 5\times 4\times 3\times 2\times 1\times 5\times 4\times 3\times 2\times 1}{8}=75600

By using formula ;n!=n(n-1)(n-2)...2\times 1

4 0
3 years ago
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