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Sever21 [200]
3 years ago
6

PLEASE HELP!!!! What is the solution of the equation 3x+2y=45

Mathematics
1 answer:
nevsk [136]3 years ago
8 0
Simplified, it"s y=-3/2x+22.5
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I need help my teacher didn’t even explain how to do this
Drupady [299]

Answer:its b

first off its a straight line ill give it that but its not going through the origin is think its b

hoped this helped lmk if it did

8 0
2 years ago
Thank you so much i might have failed my test if it wasn't for you thanks
antoniya [11.8K]

Answer:

okay

Step-by-step explanation:

3 0
3 years ago
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For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
Which is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively?
WARRIOR [948]

Answer:

Which is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively? 204.

Step-by-step explanation:

Have a great summer.

8 0
3 years ago
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Select the correct solution in each column of the table.
aalyn [17]

Answer:

Can you take a picture of the problem to see if i could help!?

Step-by-step explanation:

5 0
3 years ago
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