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3 years ago

PlZ help me like fr. brainliest?

Mathematics

1 answer:

Nookie1986 [14]3 years ago

7 0

Answer:

∠a = 60°

∠b = 60°

∠c = 120°

∠d = 60°

Step-by-step explanation:

I have a couple things attached that should help. In the first attachment I've assigned all the angles with their congruent counterparts. I've also assigned the value 60 degrees with a (z) to help visualize all the degrees that are 60 degrees.

So first of all we can deduce that the angles represented by z up in the far left corner equal 60 degrees. We notice that the four angles that make up the intersection in that corner equal 360 degrees total. So we can find the angles of the other two mystery angles by adding 60+60.

60/60 = 120

120 is the sum of two of the angles. We need 2 more. We know that the remaining two angles are congruent, due to just two lines being intersected. Thus, we can subtract 120 from 360 and get the sum of those two angles.

360-120 = 240

Divide by 2, to get the degrees of each individual angle.

240/2 = 120

So two angles in the upper left-hand corner are 60 degrees, and the other two congruent angles are 120 degrees. This can be seen in the second attachment.

Now we can solve for almost the rest of the angles. Notice the triangle that angles a, b, and the inside corner in the upper left hand corner make. We know that a triangle has 180 degrees. We also know that one angle is 60 degrees.

180-60 = 120

Divide by two to get the degrees of each individual angle.

120/2 = 60

Both ∠a and ∠b are 60°

Next, because we know ∠b is 60 degrees, we also know that b's reflectory angle equals 60 degrees. Since there are six angles in the lower middle angle, we can add up the four angles we already know to begin to solve for ∠d. We will be using the value 2d to represent ∠d and its congruent angle as they both have the same measurement of degrees.

60+60+60+60+2d = 360

240 + 2d = 360

2d = 120

d = 60

∠d and its congruent angle both equal 60°

We're almost done! Since we know that both ∠a (that we now know it is 60 degrees) and ∠c rest on a straight line, we know that the sum of both ∠a and ∠c is going to equal 180°.

60+c = 180

Subtract 60 from 180 to get c.

∠c = 120

Hope this helped!

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Answer:

More clarification

Step-by-step explanation:

2 of a white ball =2/30 =1/15;

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Let the number of black ball be X

x/(x +20)= 1/15[ probability of picking black ball ]

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4 years ago

What is 9/16 + 1/2 simplified

trasher [3.6K]

$\frac{9}{16}$ + $\frac{1}{2}$

First, find the least common denominator (LCD) of the two fractions.
Multiples of 16: 16
Multiples of 2: 2, 4, 6, 8, 10, 12, 14, 16
The LCD is 16.
Second, make the denominators the same as the LCD. / Your problem should look like: $\frac{9}{16}$ + $\frac{1x8}{2x8}$
Third, simplify. The denominators are now the same. / Your problem should look like: $\frac{9}{16}$ + $\frac{8}{16}$
Fourth, join the denominators. / Your problem should look like: $\frac{9+8}{16}$
Fifth, simplify. / Your problem should look like: $\frac{17}{16}$
Sixth, convert to mixed fraction. / Your problem should look like: $1 \frac{1}{16}$

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8 0

3 years ago

Consider an object moving along a line with the given velocity v. Assume t is time measured in seconds and velocities have units

Lady_Fox [76]

Answer:

a. the motion is positive in the time intervals: $[0,2)U(6,\infty)$

The motion is negative in the time interval: (2,6)

b. S=7 m

c. distance=71m

Step-by-step explanation:

a. In order to solve part a. of this problem, we must start by determining when the velocity will be positive and when it will be negative. We can do so by setting the velocity equation equal to zero and then testing it for the possible intervals:

$3t^{2}-24t+36=0$

so let's solve this for t:

$3(t^{2}-8t+12)=0$

$t^{2}+8t+12=0$

and now we factor it again:

(t-6)(t-2)=0

so we get the following answers:

t=6 and t=2

so now we can build our possible intervals:

$[0,2) (2,6) (6,\infty)$

and now we test each of the intervals on the given velocity equation, we do this by finding test values we can use to see how the velocity behaves in the whole interval:

[0,2) test value t=1

so:

$v(1)=3(1)^{2}-24(1)+36$

v(1)=15 m/s

we got a positive value so the object moves in the positive direction.

(2,6) test value t=3

so:

$v(1)=3(3)^{2}-24(3)+36$

v(3)=-9 m/s

we got a negative value so the object moves in the negative direction.

$(6,\infty)$ test value t=7

so:

$v(1)=3(7)^{2}-24(7)+36$

v(1)=15 m/s

we got a positive value so the object moves in the positive direction.

the motion is positive in the time intervals: $[0,2)U(6,\infty)$

The motion is negative in the time interval: (2,6)

b) in order to solve part b, we need to take the integral of the velocity function in the given interval, so we get:

$s(t)=\int\limits^7_0 {(3t^{2}-24t+36)} \, dt$

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{7}_{0}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{7}_{0}$

so now we evaluate the integral:

$s=7^{3}-12(7)^{2}+36(7)-(0^{3}-12(0)^{2}+36(0))$

s=7 m

for part c, we need to evaluate the integral for each of the given intervals and add their magnitudes:

[0,2)

s(t)=\int\limits^2_0 {(3t^{2}-24t+36)} \, dt

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{2}_{0}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{2}_{0}$

so now we evaluate the integral:

$s=2^{3}-12(2)^{2}+36(2)-(0^{3}-12(0)^{2}+36(0))$

s=32 m

(2,6)

s(t)=\int\limits^6_2 {(3t^{2}-24t+36)} \, dt

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{6}_{2}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{6}_{2}$

so now we evaluate the integral:

$s=6^{3}-12(6)^{2}+36(6)-(2^{3}-12(2)^{2}+36(2))$

s=-32 m

(6,7)

s(t)=\int\limits^7_6 {(3t^{2}-24t+36)} \, dt

so we get:

$s(t)=[\frac{3t^{3}}{3}-\frac{24t^{2}}{2}+36]^{7}_{6}$

which simplifies to:

$s(t)=[t^{3}-12t^{2}+36t]^{7}_{6}$

so now we evaluate the integral:

$s=7^{3}-12(7)^{2}+36(7)-(6^{3}-12(6)^{2}+36(6))$

s=7 m

and we now add all the magnitudes:

Distance=32+32+7=71m

7 0

3 years ago

Help please! I attached the picture you get 20 points!!

Wittaler [7]

Answer:

<1=48

<2=132

<3=48

Step-by-step explanation:

We know that <2 is also 132

Since a line is 180, we can do 180-132=48

That means <1 and <3 are 48

To check we can add them all together and get 360

5 0

3 years ago

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