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VashaNatasha [74]
3 years ago
9

Emma is 9 1/4 years old . how many months is Emma please answer

Mathematics
2 answers:
coldgirl [10]3 years ago
5 0
Well we know there are 12 months in 1 year
So since she lived 9 already lets multiply that
12 x 9 = 108
so far she lived 108 months but wait! we still need to add 1/4 of a year
lets find out how many months 1/4 of a year is by dividing 12 and 4 
sooo heres the math
12 ÷ 4 = 3
so she lived another 3 months.
Lets add on 108 and 3
108 + 3 = 111
so she lived 111 months her entire life
hope this helps 
and dont forget 2 
MARK ME BRAINLIEST! :P
xeze [42]3 years ago
4 0
There are 12 months in a year so 9 x 12 = 108. 1/4 is equivalent to 3/12 because you multiply the numerator and denominator by 3. 108 + 3 = 111.
Emma is 111 months old. Hope this helps!
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Step-by-step explanation:

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A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural freq
oksano4ka [1.4K]

Answer:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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\bar X represent the sample mean for the sample  

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The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And for this case we know that the 95% confidence interval is given by:

\bar X=\frac{233.002 +229.266}{2}= 231.134

And the margin of error is given by:

ME = \frac{233.002 -229.266}{2}= 1.868

And the margin of error is given by:

ME= t_{\alpha/2} \frac{s}{\sqrt{n}}

The degrees of freedom are given by:

df = n-1 = 5-1=4

And the critical value for 95% of confidence is t_{\alpha/2}= 2.776

So then we can find the deviation like this:

s = \frac{ME \sqrt{n}}{t_{\alpha/2}}

s = \frac{1.868* \sqrt{5}}{2.776}= 1.506

And for the 99% confidence the critical value is: t_{\alpha/2}= 4.604

And the margin of error would be:

ME = 4.604 *\frac{1.506}{\sqrt{5}}= 3.098

And the interval is given by:

Lower = 231.134- 3.098=228.036

Upper = 231.134+ 3.098=234.232

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