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3 years ago

Emma is 9 1/4 years old . how many months is Emma please answer

2 answers:

5 0

Well we know there are 12 months in 1 year
So since she lived 9 already lets multiply that
12 x 9 = 108
so far she lived 108 months but wait! we still need to add 1/4 of a year
lets find out how many months 1/4 of a year is by dividing 12 and 4
sooo heres the math
12 ÷ 4 = 3
so she lived another 3 months.
Lets add on 108 and 3
108 + 3 = 111
so she lived 111 months her entire life
hope this helps
and dont forget 2
MARK ME BRAINLIEST! :P

xeze [42]3 years ago

4 0

There are 12 months in a year so 9 x 12 = 108. 1/4 is equivalent to 3/12 because you multiply the numerator and denominator by 3. 108 + 3 = 111.
Emma is 111 months old. Hope this helps!

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a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

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Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

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