2. IQS = 4 and QR is a perpendicular bisector of TS , determined which of the following claims is true
1 answer:
You might be interested in
This question is incomplete because it lacks the appropriate attachment containing the argument of Paul and Manuel
Kindly find attached the appropriate attachment necessary to solve this question.
The attachment was sourced online
Answer:
a) Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X
Step-by-step explanation:
From the above question, we are given two shapes: Cone W and Square Pyramid
Cone W: Radius = 8cm, Height = 5cm
Volume of a Cone = 1/3 πr²h
Where π = 3.14
Volume of Cone X = 1/3 × 3.14 × 8² × 5
= 334.93cm³
For Square pyramid X
Volume = 1/3 × Base Area × Height
Base Area of Cone W = Base Area of square pyramid X = πr²
Where π = 3.14
Base area = 3.14 × 8² = 200.96cm²
Height of Square pyramid X = Height of Cone W = 5cm
Volume of Square pyramid = 1/3 ×200.96cm² × 5cm
= 334.93cm³
Therefore, from my above calculation and compared with the arguments of Paul and Manuel, Option a) "Paul's argument is correct, Manuel used the wrong formula to find the volume of square pyramid X" is the correct option.
The reason why is because the correct formula for the volume of a square pyramid = 1/3 × Base area × Height
This was the formula Paul used.
Manuel on the other hand used the formula: Base Area × Height to find the volume of cone W. This formula is wrong.
Option a, is the correct answer.
Answer:
49.5 square inches
Step-by-step explanation:
We can split the figure into two easier shapes to find the area of; a triangle and a square.
The formula for a triangle is (b*h)1/2. Once we solve we get 24.5 or 24 1/2.
The formula for a square is l*w. Once we solve we get 25.
To find the area of the shaded region, we would add both area and get 49.5 or 49 1/2 square inches.
