All categories

3 years ago

Can someone please help me with question 42?

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

8 0

These angles should add to 180 degrees because the angles are on a straight line so you should use the formula x=180-90-38. Therefore, x should be 52 degrees

You might be interested in

Breaking apart 6×6 to find product

IgorLugansk [536]

I think it would be 3

4 0

2 years ago

Read 2 more answers

How do I write an equation that would allow someone to find the value of R

Ivahew [28]

Answer:

R+239=3501

Step-by-step explanation:

Add the three 1,167 values together and you get 3,501. Then, because we know a portion of the three blocks is equal to 239, add it so when we solve for R, 239 is subtracted from the total.

As for solving it,

Subtract 239 on both sides, and R is 3501-239 = 3262

6 0

3 years ago

Find a cartesian equation for the curve and identify it. r = 10 tan(θ) sec(θ)

Vilka [71]

For a cartesian equation
$x=r\cos\theta \ and \ y=r\sin\theta \\ \\ \cos\theta=\frac{x}{r} \ and \ \sin\theta=\frac{y}{r} \\ \\ \tan\theta=\frac{\sin\theta}{\cos\theta}=\frac{y}{r}\cdot\frac{r}{x}=\frac{y}{x} \\ \\ \sec\theta=\frac{1}{\cos\theta}=\frac{r}{x}$

Given r = 10 tan(θ) sec(θ)
$r=10\tan\theta\sec\theta=10\cdot\frac{y}{x}\cdot\frac{r}{x} \\ \\ \Rightarrow10y=x^2 \\ \\ \Rightarrow y= \frac{1}{10} x^2$

Therefore,the curve is a parabola opening upward with vertex (0, 0).

3 0

3 years ago

Scientist can determine the age of ancient objects by a method called radiocarbon dating. The bombardment of the upper atmospher

Artemon [7]

Answer: 2500 years

Step-by-step explanation:

I'm not quite sure if I'm doing this right myself but I'll give it a shot.

We use this formula to find half-life but we can just plug in the numbers we know to find t.

$A(t)=A_{0}(1/2)^t^/^h$

We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For $A_{0$ let's just assume that there are 100 original atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. h is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.

$74=100(1/2)^t^/^5^7^3^0$

Now, solve. First, divide by 100.

$0.74=(0.5)^t^/^5^7^3^0$

Take the log of everything

$log(0.74)=\frac{t}{5730} log(0.5)$

Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the t and get

$5730\frac{log(0.74)}{log(0.5)} =t$

Use your calculator to solve that giant mess for t and you'll get that t is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.

Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.

5 0

3 years ago

Solve for x: x - 9 = 15 A. 6 B. 24 C. -24 D. -6

Oduvanchick [21]

Answer:

X = 24

Step-by-step explanation:

Add 9 To Both Sides

X - 9 + 9 = 15 + 9

Simplify

X = 24

Best Of Luck,

- I.A. -

4 0

3 years ago

Read 2 more answers