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zzz [600]
3 years ago
11

Given that x and y vary directly, write the equation relating x and y if x = 3 when y = 24.

Mathematics
1 answer:
Stels [109]3 years ago
6 0

Answer:

y = 1/8 x

Step-by-step explanation:

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A grocer mixes peanuts that cost $2.49 per pound and walnuts that cost $3.89 per pound to make 100 pounds of a mixture that cost
ANTONII [103]

Let a be the amount of peanuts; and

Let b the amount of walnuts

 

Equation 1 would be: A + B = 100

249a + 389b = 319 (100)

Equation 2 would be: 249a + 389b = 31900

 

From equation 1:

a = 100 – b

249 (100 – b) + 389b = 31900

24900 – 249b + 389b = 31900

140b = 7000

b = 50 lbs

 

then from equation 1:

A + 50 = 100

A = 50 pounds

5 0
3 years ago
Aaron is growing two plants. At the last measurement,the first plant was 6.53 inches tall and the second was 2.7 inches tall.
AlekseyPX
Just subtract the two numbers and the answer is 3.83 inches
5 0
4 years ago
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How to write 21/6 as a mixed number
NNADVOKAT [17]
Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.

3 and 3 over 6

5 0
3 years ago
Two fair dice are rolled. Determine whether the events are dependent or independent. (a) (the first die shows 3) and (the two di
Alborosie

Answer: The events are independent

a) p = 1/36 b) p = 5/216

Step-by-step explanation: both events are independent because the fact that the first die shows it sample space {1, 2, 3, 4, 5, 6} does not stop the second die from showing it own sample space too which is {1, 2, 3, 4, 5, 6}.

The sample space of first die = {1, 2, 3, 4, 5, 6}

The sample space of second die = {1, 2, 3, 4, 5, 6}

The sample space of 2 dice rolled at once is seen as attachment to this answer, find attachment below.

Probability that an event will occur = number of time the event will occur / total number of possible outcome of the event

a)

Probability that first die will show 3 = number of times 3 shows up in the event / total number of outcome of the die = P (3)

P (3) = 1/6

Probability that 2 dice sum up to give 7 = 6/ 36 = 1/6 ( from the sample space for 2 dice attached, it is seen that the sum of 7 comes out 6 times and the total sample space is 36)

P (first die show 3) = 1/6

P ( 2 dice sum to 7) = 1/6

P ( first die show 3) and P ( 2 dice sum to 7) = 1/6 * 1/6 = 1/36.

b)

Probability of the first die showing 4 = P(4) = 1/6

Probability of 2 die sum up to give 8 = 5/36

P ( first die show 8) and P ( 2 die sum up to give 8) = 1/6 * 5/36 = 5/216

7 0
3 years ago
Simplify completely quantity 2 x squared plus 16 x plus 30 all over quantity 5 x squared plus 13 x minus 6.
Ludmilka [50]
(2x^2 + 16x + 30) / (5x^2 + 13x -6)
Start by factoring the numerator and denominator.
Cancel any like factors.

2(x^2 + 8x + 15)
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2(x + 5) / (5x - 2)
The third choice
8 0
3 years ago
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