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Dmitry [639]
3 years ago
12

What's the 32nd term for the sequence 16,10,4,-2

Mathematics
1 answer:
Deffense [45]3 years ago
6 0
Minnus 4 each time
first term is 16
an=a1+d(n-1)
a1=first term
d=common diffferentice

a1=16
d=-4

an=16-4(n-1)
32nd term
n=32

a32=16-4(32-1)
a32=16-4(31)
a32=16-124
a32=-108

the 32nd term is -108
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Step-by-step explanation: This problem states that the sum of three consecutive integers is -354 and it asks us to find the integers. Three consecutive integers can be represented as followed.

X ⇒ <em>first integer</em>

X + 1 ⇒ <em>second integer</em>

X + 2 ⇒<em> third integer</em>

<em />

Since the sum of our three consecutive integers is -354, we can set up an equation to represent this.

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