Question

to solve the system of equations below, grace isolated the variable y in the first equation and then substituted into the second equation. what was the resulting equation? 3y=12x x^2/4+y^2/9=1

Answer 1

Answer:

The resulting equation is

x^2/4+16x^2/9=1

Step-by-step explanation:

The given equations are:

3y=12x   eq(1)

x^2/4+y^2/9=1    eq(2)

We need to isolate variable y in equation 1

Divide both sides of the equation with 3

3y/3 = 12x/3

y = 4x

Now, substitute the value of y=4x in second equation

x^2/4+y^2/9=1

x^2/4 + (4x)^2/9 = 1

The resulting equation is

x^2/4+16x^2/9=1

Answer 2

Answer:

$\frac{x^2}{4}+\frac{(4x)^2}{9}=1$

Step-by-step explanation:

Given system of equations,

$3y=12x-----(1)$

$\frac{x^2}{4}+\frac{y^2}{9}=1----(2)$

As per statement,

Isolating the variable y in the first equation,

$y=\frac{12}{3}x=4$

Now, substituting into the second equation,

$\frac{x^2}{4}+\frac{(4x)^2}{9}=1$

Which is the resulting equation,

Simplifying the equation,

$\frac{x^2}{4}+\frac{16x^2}{9}=1$

$\frac{9x^2+64x^2}{36}=1$

$73x^2=36$