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ella [17]
4 years ago
5

to solve the system of equations below, grace isolated the variable y in the first equation and then substituted into the second

equation. what was the resulting equation? 3y=12x x^2/4+y^2/9=1
Mathematics
2 answers:
Marizza181 [45]4 years ago
8 0

Answer:

The resulting equation is

x^2/4+16x^2/9=1

Step-by-step explanation:

The given equations are:

3y=12x   eq(1)

x^2/4+y^2/9=1    eq(2)

We need to isolate variable y in equation 1

Divide both sides of the equation with 3

3y/3 = 12x/3

y = 4x

Now, substitute the value of y=4x in second equation

x^2/4+y^2/9=1

x^2/4 + (4x)^2/9 = 1

The resulting equation is

x^2/4+16x^2/9=1

larisa [96]4 years ago
6 0

Answer:

\frac{x^2}{4}+\frac{(4x)^2}{9}=1

Step-by-step explanation:

Given system of equations,

3y=12x-----(1)

\frac{x^2}{4}+\frac{y^2}{9}=1----(2)

As per statement,

Isolating the variable y in the first equation,

y=\frac{12}{3}x=4

Now, substituting into the second equation,

\frac{x^2}{4}+\frac{(4x)^2}{9}=1

Which is the resulting equation,

Simplifying the equation,

\frac{x^2}{4}+\frac{16x^2}{9}=1

\frac{9x^2+64x^2}{36}=1

73x^2=36

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