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vaieri [72.5K]
4 years ago
13

How do you make 28/6 in to a mixed fraction in simplest form

Mathematics
2 answers:
DaniilM [7]4 years ago
4 0
You do 6 divided by 28 Which is 4 than the mixed number is 4 and the fraction is 6/28
JulsSmile [24]4 years ago
3 0
28/6 is 4 2/3 in simplest form

The way we arrive at this answer is
6 can be divided from 28 at least 4 times maximum.
6 times 4 is 24.
28 - 24 = 4.
The 6's that have been taken away from the fraction becomes 1's, because 6/6 is equivalent to 1.
Therefore, 1 times 4 is 4, because we had taken away from the fraction 4 times.
What you get is 4 4/6. However, that is not in simplest form yet.
4/6 can be simplified to 2/3 by dividing by two.

The answer you should get is 4 2/3
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Verdich [7]
I don’t see a point so how am I supposed to answer
8 0
3 years ago
6x+32=−2x
velikii [3]
Whatever you do to one side, you have to do to the other.
Try to get all the x values and regular values together.
To do that, just subtract both sides by 6x to cancel it out on one side and subtract it from the other side:

6x-6x+32=-2x-6x
=
32=-8x
now divide both sides by -8 to get the x by itself

32/-8=-8/-8x
= 32/-8=x
-4=x
so your answer is: x= -4
5 0
4 years ago
What is another way to write this number 300+70+5/10+8/100
trasher [3.6K]
The answer is 370.58
5 0
3 years ago
Read 2 more answers
(14+42-6)/10+7^2 order of operation
Rainbow [258]

Answer:

54

Step-by-step explanation:

\dfrac{(14+42-6)}{10}+7^2

Parentheses (14 + 42 - 6) = 50:

⇒ 50/10 + 7²

Exponents 7² = 49:

⇒ 50/10 + 49

Multiplication/division  50/10 = 5:

⇒ 5 + 49

Addition/subtraction:  5 + 49 = 54

⇒ 54

6 0
3 years ago
If someone could help me with number 26...
Volgvan
Given:
\text{sec x} -  \sqrt{\text{2 sec x}-1} =0

Solution:
To solve the equation, it would be best if we remove the root. We remove the root by squaring the equation, but first we need to move the root and the content to the left side.
\text{sec x} -  \sqrt{\text{2 sec x}-1} =0
\text{sec x} =  \sqrt{\text{2 sec x}-1}

Then square both side to remove the root
\text{sec}^2 x= \text{2 sec x}-1

After removing the root, move all terms to the left side
sec² x - 2 sec x + 1 = 0

Do factorization, remember that
a² - 2a + 1 = (a - 1)²
So,
sec² x - 2 sec x + 1 = 0
(sec x - 1)² = 0
sec x - 1 = 0
sec x = 1
\dfrac{1}{\text{cos x}} = 1
cos x = 1
cos x = cos 0°
x = 0°
8 0
3 years ago
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