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3 years ago

How do I get the answer to this problem

Mathematics

2 answers:

Mashcka [7]3 years ago

5 0

Answer: $\frac{19}{20} - \frac{10}{20} - \frac{2}{20}$

$\frac{7}{20}$

Step-by-step explanation:

Since the Least Common Denominator is 20 (or the biggest number on the bottom in your case), you can multiply 4 and 10 by their corresponding number to get 20.

4 * 5 = 20

10 * 2 = 20

Now multiply the top and bottom by 5 and 2

$\frac{5}{5} *\frac{2}{4}$ = $\frac{10}{20}[tex]\frac{2}{2} *\frac{1}{10}$ = $\frac{2}{20}Now subtract everything.[tex]\frac{19}{20} - \frac{10}{20} - \frac{2}{20}$

Its equals $\frac{7}{20}$ .

N76 [4]3 years ago

3 0

Answer:

You do it, or ask someone

Step-by-step explanation:

Because. Just because. That's logic.

jk.... 19/20 - 10/20 - 2/20

19/20 - 12/20

7/20

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11d = -44
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3 years ago

A ball is thrown vertically in the air with a velocity of 90ft/s. Use the projectile formula h=−16t2+v0t to determine at what ti

Debora [2.8K]

Answer:

$t=1.7 \ sec\ , t=4.0\ sec$

Step-by-step explanation:

Vertical Throw

It refers to a situation where an object is thrown verticaly upwards with some inicial speed v_o and let in free air (no friction) until it completes its movement up and finally returns to the very same point of lauch. The only acting force is gravity

The projectile formula is given as

$h=-16t^2+v_0t$

where t is time in seconds, h is the height in feet and v is the speed in ft/sec

We are required to find the time t where h=120 ft, knowing $v_o=90\ ft/sec$

$-16t^2+90t=120$

Rearranging

$-16t^2+90t-120=0$

This is a second-degree equation which will be solved with the formula

$\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\displaystyle x=\frac{-90\pm \sqrt{90^2-4(-16)(-120)}}{2(-16)}$

$\displaystyle x=\frac{-90\pm \sqrt{1380}}{-32}$

Two solutions are obtained

$\boxed{t=1.7 \ sec\ , t= 4.\ sec}$

Both solutions are possible because the ball actually is at 120 ft in its way up and then when going down

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3 years ago

Read 2 more answers

E If M P = Rs 420,SP. 405 then find discount

Leni [432]

Answer:

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Step-by-step explanation:

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3 years ago

A tank is filled with 1000 liters of pure water. Brine containing 0.04 kg of salt per liter enters the tank at 9 liters per minu

klemol [59]

Answer:

The differential equation which describes the mixing process is $\frac{dc_{salt,out}}{dt} + \frac{2}{125}\cdot c_{salt,out} = \frac{71}{100000}$ .

Step-by-step explanation:

The mixing process within the tank is modelled after the Principle of Mass Conservation, which states that:

$\dot m_{salt,in} - \dot m_{salt,out} = \frac{dm_{tank}}{dt}$

Physically speaking, mass flow of salt is equal to the product of volume flow of water and salt concentration. Then:

$\dot V_{water, in, 1}\cdot c_{salt, in,1} + \dot V_{water, in, 2} \cdot c_{salt,in, 2} - \dot V_{water, out}\cdot c_{salt, out} = V_{tank}\cdot \frac{dc_{salt,out}}{dt}$

Given that $\dot V_{water, in, 1} = 9\,\frac{L}{min}$ , $\dot V_{water, in, 2} = 7\,\frac{L}{min}$ , $c_{salt,in,1} = 0.04\,\frac{kg}{L}$ , $c_{salt, in, 2} = 0.05\,\frac{kg}{L}$ , $\dot V_{water, out} = 16\,\frac{L}{min}$ and $V_{tank} = 1000\,L$ , the differential equation that describes the system is: