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yuradex [85]
3 years ago
14

The accounting number format function is contained within the __________.

Computers and Technology
1 answer:
bija089 [108]3 years ago
8 0
The accounting number format shows numbers with a dollar sign on one side of the number, embeds a comma each three positions to one side of the decimal point, a presentations numbers to the closest cent. Hope this will help.
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A robot worker and a human worker are both vulnerable to
Lady bird [3.3K]

Answer:

fire

Explanation:

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3 years ago
A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st
Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

^nC_r = \frac{n!}{(n-r)!r!}

Where n = 15\ and\ r = 4

^{15}C_4 = \frac{15!}{(15-4)!4!}

^{15}C_4 = \frac{15!}{11!4!}

^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}

^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}

^{15}C_4 = \frac{32760}{24}

^{15}C_4 = 1365

<em>Hence, there are 1365 ways </em>

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

<em>From the given parameters; 3 out of 15 is detective;</em>

So;

p = 3/15

p = 0.2

q = 1 - p

q = 1 - 0.2

q = 0.8

Solving further using binomial;

(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

Probability =  ^nC_3pq^3

Substitute 4 for n, 0.2 for p and 0.8 for q

Probability =  ^4C_3 * 0.2 * 0.8^3

Probability =  \frac{4!}{3!1!} * 0.2 * 0.8^3

Probability = 4 * 0.2 * 0.8^3

Probability = 0.4096

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

<em>Probability that at least one is defective + Probability that at none is defective = 1</em>

Probability that none is defective is calculated as thus;

Probability =  q^n

Substitute 4 for n and 0.8 for q

Probability =  0.8^4

Probability = 0.4096

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0
3 years ago
PLEASE HELP ASAP i will mark brilliant
Ray Of Light [21]
1. Cyberbullying
2.Confide in an adult you trust, such as a teacher or a parent
3.It is easy to miscommunicate  and escalate the situation in an online environment

Cyberbully hurts people, so NEVER post something that could hurt someone's feelings

Hope this helps!
3 0
3 years ago
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While storms could be a cause, power______ are more likely to be caused by disturbances from high-demand equipment in a home or
Troyanec [42]

Answer:

outages

Explanation:

While storms could be a cause, power <u>outages</u> are more likely to be caused by disturbances from high-demand equipment in a home or building

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2 years ago
Which of the following items is not considered a personal risk factor for ergonomic hazards? A. Body size B. Medical condition C
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I think it might be a. body size .
6 0
3 years ago
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