How do i solve for x and y here?

What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a

laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

$x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5$

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

$M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x$

So, the mean of 11 consecutive integers is the 6th integer.

4 0

3 years ago

70% of the world's snake species lay eggs, while the remaining ones give birth to live young. If there are 2,700 different speci

igomit [66]

If 70% lay eggs, that leaves the remaining 30% to give live birth. 2700(0.30) = 810 species

8 0

3 years ago

-2(3x-3)=4x please help solve for x=

Llana [10]

Answer:

exact form:

x= 3/5

Decimal form:

x=0.6

6 0

2 years ago

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Find the sum and express it in simplest form. (ab+4a-6)+(ab+6)

riadik2000 [5.3K]

= 2ab + 4a + 6 - 6

= 2ab + 4a

you can factor this to 2a(b + 2)

3 0

3 years ago

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A cylindrical container of height 28cm and diameter 18cm is filled with water.The water is then poured into another container wi

Harman [31]

Answer:

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Asked on December 20, 2019 by

Ziya Vïvəķ

A cylindrical container with diameter of base 56cm contains sufficient water to submerge a rectangular solid of iron with dimensions (32×22cm×14cm). Find the rise in the level of water when the solid is completely submerged.

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ANSWER

Given,

Diameter of the base of the cylindrical container d=56 cm

Hence, radius of the base of the cylindrical container r=

2

56

=28 cm

Dimensions of rectangular solid is (32 cm×22 cm×14 cm)

We know that when a body is completely submerged in a container containing water,

the rise in the volume of water in the container is equal to the volume of the body.

Let, the water rises to a height h.

Hence,

Volume of water rises in cylindrical container =Volume of the rectangular solid

πr

2

h=32×22×14 cm

3

7

22

×(28)

2

×h=9856 cm

h=

22×784

9856×7

cm

h=4 cm

4 0

3 years ago

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