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3 years ago

7

Write a two-column proof.

1 answer:

Tpy6a [65]3 years ago

5 0

Answer with Step-by-step explanation:

Since we have given that

Angle 12 and angle 11 are complementary.

Mathematically, it is expressed as

$\angle 12+\angle 11=90^\circ$ ------------(1)

measure of angle 10 + measure of angle 11 = 90 degrees.

Mathematically, it is expressed as

$\angle 10+\angle 11=90^\circ$ ----------------(2)

From eq(1), and eq(2), we get that

$\angle 12+\angle 11=\angle 10+\angle 11\\\\\angle 12=\angle 10$

Hence, angle 12 is congruent to angle 10.

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Someone help me with this.

Mandarinka [93]

Answer:

2x² + 13x + 15

Step-by-step explanation:

| 2x | 3

x | 2x*x = 2x² | 3*x = 3x

5 | 2x*5 = 10x | 3*5 = 15

We have, 2x² + 3x + 10x + 15

Combining like terms, we would have the final expression as:

2x² + 13x + 15

3 0

2 years ago

Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

i)

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

8 0

3 years ago

☆pls help no one has helped me and I'm so confused!

motikmotik

Answer:

Step-by-step explanation:

a). $\frac{5\pm\sqrt{-4}}{3}$ = $\frac{5}{3}\pm \frac{\sqrt{-4}}{3}$

= $\frac{5}{3}\pm\frac{2\sqrt{(-1)} }{3}$

= $\frac{5}{3}\pm\frac{2i}{3}$ [Since, i = $\sqrt{(-1)}$ ]

b). $\frac{10\pm\sqrt{-16}}{2}$ = $\frac{10}{2}\pm \frac{\sqrt{-16}}{2}$

= $5\pm \frac{4\sqrt{-1}}{2}$

= 5 ± 2i [Since, i = $\sqrt{(-1)}$ ]

c). $\frac{-3\pm \sqrt{-144}}{6}$ = $-\frac{3}{6}\pm \frac{\sqrt{-144}}{6}$

= $-\frac{3}{6}\pm \frac{12\sqrt{-1}}{6}$

= $-\frac{1}{2}\pm 2\sqrt{-1}$

= $-\frac{1}{2}\pm 2i$ [Since, i = $\sqrt{(-1)}$ ]

4 0

2 years ago

What value(s) of x make the following expression undefined? x^2+ 1

allsm [11]

Answer:x=2

Step-by-step explanation: 2x-4=0

2x-4=0

+4 +4

2x=4

2x/2=4/2

X=2

5 0

3 years ago

HELLLPPPPPPP!!!!!!!!!!!!!!!

Vlada [557]

The answer would be 34

3 0

3 years ago