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aksik [14]
3 years ago
5

If the margin of error in an estimate for the mean weight of a shipment is + or -2 pounds at a confidence level of 95 percent, w

hat will be the margin of error at a confidence level of 98 percent? Be sure to show how you arrived at your answer.
Mathematics
1 answer:
posledela3 years ago
7 0
The z-value for a confidence level of 95% is 1.960, and for a confidence level of 98% is 2.326.
The MoE at a confidence level of 98% will become:
2\times\frac{2.326}{1.960}=2.373\ pounds
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3 machine

Step-by-step explanation:

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Use the rules of exponents to evaluate or simplify. Write without negative exponents. 1/4^-1/2 = ___ a0
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For this case we have, by definition:


a^{-b} =\frac{1}{a ^ b}

So, we have:


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On the other hand we have that by definition:


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Thus, the expression can be written as:


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\frac{1}{4}^{-\frac{1}{2}}= 2


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3 years ago
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