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aksik [14]
3 years ago
5

If the margin of error in an estimate for the mean weight of a shipment is + or -2 pounds at a confidence level of 95 percent, w

hat will be the margin of error at a confidence level of 98 percent? Be sure to show how you arrived at your answer.
Mathematics
1 answer:
posledela3 years ago
7 0
The z-value for a confidence level of 95% is 1.960, and for a confidence level of 98% is 2.326.
The MoE at a confidence level of 98% will become:
2\times\frac{2.326}{1.960}=2.373\ pounds
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Grampy $12 for 4 baseball packs James paid 28 for seven who got a better deal baseball card packs? And why
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Answer:

Grampy

Step-by-step explanation:

                money      cards

Grampy=   $12             4 packs

 James=    $28            7 packs

12*2= 24 dollars and 8 packs

while James payed 28 dollars for 7 packs

So Grampy got a better deal.

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Mike is picking out 4 books to read out of collection of 12. How many ways can the books be picked?
AURORKA [14]
3 sets or it you could divide which would still give you 3
6 0
4 years ago
Read 2 more answers
FIND THE VOLUME
galben [10]

1. The figure is a prism: V = lwh = (12.1)(5.3)(4.2) = 269.3 cu. cm.


2. The figure is also a prism but the base is triangular: V = 1/2*b*h*l = 1/2*(13)*(sqrt(3)/2*13)*24 = 1756.3 cu. yd.


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

8 0
3 years ago
The table below lists the masses and volumes of several pieces of the same type of metal. There is a proportional relationship b
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8 0
4 years ago
Given: m
Nutka1998 [239]

Answer:

m\angle MEJ=25^{\circ}.

Step-by-step explanation:

The arcs LY, KM, KL and MJ together form the full revolution angle, thus

4x+50^{\circ}+6x+x+10^{\circ}+4x=360^{\circ},\\ \\15x=300^{\circ},\\ \\x=20^{\circ}.

Note that

m\angle MOJ=4x=80^{\circ},

then

m\angle MLJ=\dfrac{1}{2}\cdot 80^{\circ}=40^{\circ}.

So,

m\angle ELM=180^{\circ}-40^{\circ}=140^{\circ}.

Also

m\angle LOK=30^{\circ},

so

m\angle KML=\dfrac{1}{2}\cdot 30^{\circ}=15^{\circ}.

In triangle EML,

m\angle MEL+m\angle EML+m\angle ELM=180^{\circ},\\ \\m\angle MEL=180^{\circ}-15^{\circ}-140^{\circ}=25^{\circ}.

Thus, m\angle MEJ=25^{\circ}.

7 0
4 years ago
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