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3 years ago

What is the domain of the function shown on the graph? A. -10

Mathematics

1 answer:

faltersainse [42]3 years ago

4 0

Answer:

Option (C)

Step-by-step explanation:

Domain of any graph is defined by the x-values or the input values of a function.

Similarly, y-values on the graph of a function define the Range.

In the graph attached, x-values varies from (-∞) to (+∞).

Therefore, Domain of the graphed function will be (-∞, ∞)

Or -∞ < x < ∞

Similarly, y-values of the graph varies from (-∞) to (1)

Therefore, range of the graphed function will be (-∞, 1).

Or -∞ < y < 1

Option (C) will be the answer.

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3 years ago

What is the slope of the line

wlad13 [49]

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2 years ago

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Hi boys can you help me pls!!!!!!!

goblinko [34]

Answer: OPTION A.

Step-by-step explanation:

Given the following function:

$h(x)=-\frac{1}{4}x^2+\frac{1}{2}x+\frac{1}{2}$

You know that it represents the the height of the ball (in meters) when it is a distance "x" meters away from Rowan.

Since it is a Quadratic function its graph is parabola.

So, the maximum point of the graph modeling the height of the ball is the Vertex of the parabola.

You can find the x-coordinate of the Vertex with this formula:

$x=\frac{-b}{2a}$

In this case:

$a=-\frac{1}{4}\\\\b=\frac{1}{2}$

Then, substituting values, you get:

$x=\frac{-\frac{1}{2}}{(2)(-\frac{1}{4}))}\\\\x=1$

Finally, substitute the value of "x" into the function in order to get the y-coordinate of the Vertex:

$h(1)=y=-\frac{1}{4}(1)^2+\frac{1}{2}(1)+\frac{1}{2}\\\\y=0.75$

Therefore, you can conclude that:

<em> The maximum height of the ball is 0.75 of a meter, which occurs when it is approximately 1 meter away from Rowan.</em>

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3 years ago

Makayla was training for a 2k run. it was tiring, and she had to stop and walk to the finish line.if she had run 650 meters out

jonny [76]

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4 years ago

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3sina-4sin4a/sin5a<br> if a=-45 degree

Ierofanga [76]

Given:

The given expression is:

$\dfrac{3\sin a-4\sin 4a}{\sin 5a}$

To find:

The value of the given expression at $a=-45$ .

Solution:

We have,

$\dfrac{3\sin a-4\sin 4a}{\sin 5a}$

Substituting $a=-45$ , we get

$\dfrac{3\sin (-45)-4\sin [4(-45)]}{\sin [5(-45)]}$

$=\dfrac{-3\sin (45)+4\sin (180)}{-\sin (225)}$

$=\dfrac{-3\sin (45)+4\sin (180)}{-\sin (180+45)}$

$=\dfrac{-3\sin (45)+4\sin (180)}{\sin (45)}$

On substituting $\sin (180)$ , we get,

$=\dfrac{-3\sin (45)+4(0)}{\sin (45)}$

$=\dfrac{-3\sin (45)+0}{\sin (45)}$

$=\dfrac{-3\sin (45)}{\sin (45)}$

$=-3$

Therefore, the value of the given expression at $a=-45$ is $-3$ .

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3 years ago