Answer:
Step-by-step explanation:
Sin(A) = 5/7
Sin(A) = 0.7143
A = sin-1(0.7143
A = 45.58
B = 180 - 45.58 - 90
B = 44.43
C = 90
c = 7
a = 5
b^2 = c^2 - a^2
b^2 = 7^2 - 5^2
b^2 = 49 - 25
b^2 = 24
b = 4.899
Answer:
The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.The terai region extends from the chure range in the north to the border of India in the south.lt covers 17 percent of total land of Nepal .this terai region is mostly flat and plain with alluvial fertile deposited by the rivers . the climate of the reason is hot and wet in summer and cold and dry in winter.Terai also called the granary of Nepal as more than half percent of people of Nepal depend on the vegetation of Terai region. Terai is plain, where more cultivation is possible. Cultivation is impossible in mountain region due to difficult topography and temperate region and even in hilly region with lots of vegetation it's not possible due to slope area. Terai is only the possible region where much cultivation is possible. Different kinds of vegetation, valuable medicinal herbs, important trees, etc. are found in Terai region. So, Terai region is called the granary of Nepal.
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Answer:
The GCF for the variable part is
k
Step-by-step explanation:
Since
18
k
,
15
k
3
contain both numbers and variables, there are two steps to find the GCF (HCF). Find GCF for the numeric part then find GCF for the variable part.
Steps to find the GCF for
18
k
,
15
k
3
:
1. Find the GCF for the numerical part
18
,
15
2. Find the GCF for the variable part
k
1
,
k
3
3. Multiply the values together
Find the common factors for the numerical part:
18
,
15
The factors for
18
are
1
,
2
,
3
,
6
,
9
,
18
.
Tap for more steps...
1
,
2
,
3
,
6
,
9
,
18
The factors for
15
are
1
,
3
,
5
,
15
.
Tap for more steps...
1
,
3
,
5
,
15
List all the factors for
18
,
15
to find the common factors.
18
:
1
,
2
,
3
,
6
,
9
,
18
15
:
1
,
3
,
5
,
15
The common factors for
18
,
15
are
1
,
3
.
1
,
3
The GCF for the numerical part is
3
.
GCF
Numerical
=
3
Next, find the common factors for the variable part:
k
,
k
3
The factor for
k
1
is
k
itself.
k
The factors for
k
3
are
k
⋅
k
⋅
k
.
k
⋅
k
⋅
k
List all the factors for
k
1
,
k
3
to find the common factors.
k
1
=
k
k
3
=
k
⋅
k
⋅
k
The common factor for the variables
k
1
,
k
3
is
k
.
k
The GCF for the variable part is
k
.
GCF
Variable
=
k
Multiply the GCF of the numerical part
3
and the GCF of the variable part
k
.
3
k