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3 years ago

What is 4 to the z power

Mathematics

1 answer:

kherson [118]3 years ago

4 0

Answer:

Step-by-step explanation: 2^2z

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NEED URGENT HELP!

sp2606 [1]

(3,9)(5,15)
slope = (15 - 9) / (5 - 3) = 6/2 = 3

y = mx + b
slope(m) = 3
(3,9)...x = 3 and y = 9
sub and find b, the y int
9 = 3(3) + b
9 = 9 + b
9 - 9 = b
0 = b

so ur equation is : y = 3x + 0....can be written as y = 3x.

after 12 months...
y = 3x...x = 12
y = 3(12)
y = 36 inches

6 0

4 years ago

(4m² - 4m²)+(-3m² -2m2 + 4 m?)

ICE Princess25 [194]

Answer:

$-5m^{2} +4m$

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

This is the one!!!!!!!!!!!

sukhopar [10]

All you have to do is move the denominator on the other side, by multiplying.

a-10
------- = -9
20

multiply 20 x -9
= -180

then it becomes a-10=-180
+10 +10
a=-170

4 0

3 years ago

Read 2 more answers

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

3 years ago

Can someone help please??

Nady [450]

Answer:

The scores in order from least likely to most likely is 8, 3, 4, and 5.

Step-by-step explanation:

1. Calculate the probability of the spinner adding up to 1, 2, 3, 4, .... 8

You will get:

2 (1/16)

3 (2/16)

4 (3/16)

5 (4/16)

6 (3/16)

7 (2/16)

8 (1/16)

2. Given the scores from the problem, the probability of each number is 3 (2/16), 4 (3/16), 5 (4/16), and 8 (1/16).

3. With this, we can determine the scores in order from least likely to most likely is 8, 3, 4, and 5.

8 0

3 years ago