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Paha777 [63]
3 years ago
13

What’s the difference between evaluating an expression for a given value of a variable and solving an equation?

Mathematics
1 answer:
Talja [164]3 years ago
6 0
The difference is that evaluating an expression for a given value is an example of let’s say In a example, the variable x is equal to 6 since 6 + 6 = 12. So it means that they are giving you the input already. SOLVING an equation is working backwards, to undo everything that has been done to the input. So you have to do the equation in order to find your answer.
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4. Add<br> f(x)= 4x?+5x-1<br> g(x) = 2x2 + 5x+3
Maurinko [17]
<h3>Answer:</h3>

A. 3x² +6

<h3>Explanation:</h3>

(f-g)(x) = f(x) -g(x) = (4x²+1) -(x²-5) . . . . . substitute the function definitions

... = 4x² +1 -x² +5 . . . . . . . . . . . eliminate parentheses

... = (4-1)x² +(1+5) . . . . . . . . . . . collect like terms

... = 3x² +6

6 0
3 years ago
What does two and five fiths equal to
erma4kov [3.2K]

2 and five fifths = 3


I hope that's help. Good night .

6 0
3 years ago
Read 2 more answers
find the equation of a cubic function whose graph passes through points (3,0) and (1,4) and is tangent to x-axis at the origin
Tomtit [17]

Answer:

y = -2x^2(x - 3)

Step-by-step explanation:

<em><u>Preliminary Remark</u></em>

If a cubic is tangent to the x axis at 0,0

Then the equation must be related to y = a*x^2(x - h)

<em><u>(3,0)</u></em>

If the cubic goes through the point (3,0), then the equation will become

0 = a*3^2(3 - h)

0 = 9a (3 - h)

0 = 27a - 9ah

from which h = 3

<em><u>From the second point, we get</u></em>

4 = ax^2(x - 3)

4 = a(1)^2(1 - 3)

4 = a(-2)

a = 4 / - 2

a = -2

<em><u>Answer</u></em>

y = -2x^2(x - 3)

 

3 0
3 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

3 0
3 years ago
To solve the equation w/8 - 4 = 20, you would first add 4 to each side and then divide each side by 8.
bearhunter [10]
False because, you DO add 4 to the sides but you would multiply the 8 because you to the opposite to cancel it out

4 0
3 years ago
Read 2 more answers
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