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shusha [124]
3 years ago
13

Classify each angle​

Mathematics
1 answer:
faltersainse [42]3 years ago
6 0

Answer:

acute: ZXB

right: WBZ, XBY, XBZ, ZBW

obtuse: YXZ,

straight: WBX, YBZ, ZBY,

not:

Step-by-step explanation:

You might be interested in
Determine the value of x. <br><br> 1) 14.75<br> 2)15.25<br> 3)11.92<br> 4)18.56
Leto [7]
Opposite angles are supplementary, the sum is 180 degrees.
6x+10+81.5=180
Combine like terms:
6x+91.5=180
Subtract 91.5 to both sides:
6x=88.5
Divide 6 to both sides:
x=14.75
The answer is 1) 14.75
Hope this helped!
3 0
2 years ago
Sin A=<br> Cos A=<br> Tan A=
natulia [17]

Sin(A) = opposite/hypotenuse = 12/13

Cos(A) = adjacent/hypotenuse = 5/13

Tan(A) = opposite/adjacent = 12/5

6 0
3 years ago
Read 2 more answers
The sum of two numbers is 80. Their difference is 22.
AVprozaik [17]

Answer:

51 + 29

Step-by-step explanation:

7 0
2 years ago
What value of c makes the equation -3c/4=24 true ?
Sonbull [250]
Creo que C es igual a -6
4 0
3 years ago
Read 2 more answers
Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 ​ )left parenthesis, 0, comma
steposvetlana [31]

Answer:

\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) \frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }.

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }

8 0
3 years ago
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