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iogann1982 [59]
3 years ago
7

The sum of two numbers is 39, twice the first number plus three times the second number is 101 find the numbers

Mathematics
1 answer:
bezimeni [28]3 years ago
3 0
The two numbers are 23 and 16 and the method is shown algebraically using simultaneous equations in the photo

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I really need help with this problem please help
VLD [36.1K]
I think the answer is going to be a

7 0
3 years ago
Can someone solve this 6x-9=3(2x-3) for me plzzzzz and thankyou <br> HANDING OUT BRAINLiEST'S
Gemiola [76]

Answer:

6x-9 = 6x -9

infinite solutions as they are the same equation.

3 0
3 years ago
If x = 100, what is the value of 3<br> Vx?
TEA [102]

Step-by-step explanation:

3vx

=3 * v * x

=3 * v * 100

=300v

4 0
2 years ago
A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
3 years ago
Please need help ASAP
andreev551 [17]

Answer:

Can u please upload more clearer pictures ?

3 0
1 year ago
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