Question

Graph the functions below. Arrange the parabolas with respect to the position of their vertices from left to right.

Answer 1

The correct answer for this question is this one:

If the x position of the vertex for f(x) is k then : 

1. f(k) => 4x+3=k, x = (k-3)/4 = (k/4)-(3/4) 
2. x = k+3 
3. x = (k+1)/2 = (k/2)-(1/2) 
4. x = 2(k+2) = 2k+4 
5. x = k+7 
6. x = k-3 
7. x = k-2 

So the order depends on the original position of the vertex k, e.g for k=0 the positions would be: 

1. -3/4 
2. 3 
3. -1/2 
4. 4 
5. 7 
6. -3 
7. -2 

So, therefore, the order would be 6 7 1 3 2 4 5

Answer 2

Answer:

6  1  3  7  2  4  5

Step-by-step explanation:

Let us initially consider that the vertex of F(x) is (0,0).

1: now for y=F(4x+3)

the vertex is $\frac{-3}{4}$.

2: for y=F(x-3)

the vertex is 3.

3: for y=F(2x-1)

the vertex is $\frac{1}{2}$.

4: for y=F(x/2-2)

the vertex is 4.

5: for y=F(x-7)

the vertex is 7.

6: for y=F(x+3)/3

the vertex is -3.

7: for y=F(x-2)

the vertex is 2.

Hence on arranging based on the vertex from left to right we get that it is arranged as:

6  1  3  7  2  4  5