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murzikaleks [220]
4 years ago
9

Graph the functions below. Arrange the parabolas with respect to the position of their vertices from left to right.

Mathematics
2 answers:
Lostsunrise [7]4 years ago
4 0
The correct answer for this question is this one:

If the x position of the vertex for f(x) is k then : 

<span>1. f(k) => 4x+3=k, x = (k-3)/4 = (k/4)-(3/4) </span>
<span>2. x = k+3 </span>
<span>3. x = (k+1)/2 = (k/2)-(1/2) </span>
<span>4. x = 2(k+2) = 2k+4 </span>
<span>5. x = k+7 </span>
<span>6. x = k-3 </span>
<span>7. x = k-2 </span>

<span>So the order depends on the original position of the vertex k, e.g for k=0 the positions would be: </span>

<span>1. -3/4 </span>
<span>2. 3 </span>
<span>3. -1/2 </span>
<span>4. 4 </span>
<span>5. 7 </span>
<span>6. -3 </span>
<span>7. -2 </span>

So, therefore, the order would be 6 7 1 3 2 4 5
zalisa [80]4 years ago
4 0

Answer:

6  1  3  7  2  4  5

Step-by-step explanation:

Let us initially consider that the vertex of F(x) is (0,0).

1: now for y=F(4x+3)

the vertex is \frac{-3}{4}.

2: for y=F(x-3)

the vertex is 3.

3: for y=F(2x-1)

the vertex is \frac{1}{2}.

4: for y=F(x/2-2)

the vertex is 4.

5: for y=F(x-7)

the vertex is 7.

6: for y=F(x+3)/3

the vertex is -3.

7: for y=F(x-2)

the vertex is 2.

Hence on arranging based on the vertex from left to right we get that it is arranged as:

6  1  3  7  2  4  5



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